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Nostrana [21]
4 years ago
12

The colors seen on the shiny side of a cd or dvd are due to

Chemistry
1 answer:
nydimaria [60]4 years ago
6 0

They are seen due to the light bouncing off of it. It is almost like a mirror so, it reflects the light so your eyes can see the bright light. Also, the colors are seen because of the light refracting. :)



~<em>Kayla :)</em>

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How many moles of H20 are in 12.4 g H20?​
UNO [17]

Answer:

12.4g of water has 0.689 moles of water.

Explanation:

Molar weight of H_{2}O = 16 + 2 = 18g

One mole of H_{2}O weighs 18g.

18g\longrightarrow1\:mole\:of\:H_{2}O\\12.4g\longrightarrow\frac{12.4}{18}=0.689\:moles\:of\:H_{2}O

Hence, 12.4g of water has 0.689 moles of water.

6 0
3 years ago
How many mL of a 15% acid solution and how many mL of a 3% acid solution must be mixed to get 45 mL of a 7% acid solution?
madam [21]

Answer:

15 mL of 15% acid solution and 30 mL of 3% acid solution

Explanation:

The total number of moles of the mixture (n_{3}) is equivalent to the addition of the number of moles of the first solution (n_{1}) and the number of moles of the second solution (n_{2}). Mathematically,

n_{1} +n_{2} = n_{3}

n_{1} = V_{1}*C_{1}

n_{2} = V_{2}*C_{2}

n_{3} = V_{3}*C_{3}

The volume of the mixture = 45 mL

The volume of first solution = x

The volume of second solution = 45 - x

Therefore:

0.15x + 0.03(45-x) = 0.07*45

0.15x + 1.35-0.03x = 3.15

0.12x = 1.8

x = 15

Thus, the volume of the first solution is 15 mL while the volume of the second solution is 30 mL.

3 0
3 years ago
4.What type of energy is used to fuel the process of photosynthesis and what type is produced in
mihalych1998 [28]

Answer:

A. light energy is used in photosynthesis and created by respiration

3 0
3 years ago
Initial Concentration mol/L[A] Initial Concentration mol/L[B] Initial Rate mol/Ls 0.20 0.10 20 0.20 0.20 40 0.40 0.20 160 Given
zimovet [89]
The generalized rate expression may be written as:
r = k[A]ᵃ[B]ᵇ

We may determine the order with respect to B by observing the change in rate when the concentration of B is changed. This can be done by comparing the first two runs of the experiment, where the concentration of A is constant but the concentration of B is doubled. Upon doubling the concentration of B, we see that the rate also doubles. Therefore, the order with respect to concentration of B is 1.
The same can be done to determine the concentration with respect to A. The rate increases 4 times between the second and third trial in which the concentration of B is constant, but that of A is doubled. We find that the order with respect to is 2. The rate expression is:

r = k[A]²[B]
4 0
3 years ago
Read 2 more answers
What is the molar mass of Pb(SO4)2? Explain how you calculated this value.
solong [7]
Hope this helps you!

3 0
3 years ago
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