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3 years ago

WHAT TIME IS IT WHERE U ARE?

Chemistry

2 answers:

Svetllana [295]3 years ago

7 0

Answer:

3:46 pm

Explanation:

ArbitrLikvidat [17]3 years ago

6 0

Answer:

8:47 p.m

Explanation:

You might be interested in

how many moles of each ion are present in 2.55 L of solution containing 23.6 g of the solute in the ionic compound NaCl

CaHeK987 [17]

Answer:

0.404 moles Na⁺ and 0.404 moles Cl⁻

Explanation:

In the solution you have 23.6g of NaCl. As molar mass of NaCl is 58.44g/mol. Moles you have present are:

23.6g NaCl × (1mol / 58.44g) = <em>0.404 moles of NaCl</em>

As you can see in the formula, each mole of NaCl contains 1 mole of Na⁺ and 1 mole of Cl⁻. Thus, moles of each ion are:

<em>0.404 moles Na⁺ and 0.404 moles Cl⁻</em>

3 0

4 years ago

How many grams S03<br> are needed to make 400g<br> H₂So4 in 49%

NemiM [27]

160 g of SO3 are needed to make 400 g of 49% H2SO4.

<h3>How many grams of SO3 are required to prepare 400 g of 49% H2SO4?</h3>

The equation of the reaction for the formation of H2SO4 from SO3 is given below as follows:

$SO_{3} + H_{2}O \rightarrow H_{2}SO_{4}$

1 mole of SO3 produces 1 mole of H2SO4

Molar mass of SO3 = 80 g/mol

Molar mass of H2SO4 = 98 g/mol

80 g of SO3 are required to produce 98 og 100%H2SO4

mass of SO3 required to produce 400 g of 100 %H2SO4 = 80/98 × 400 = 326.5 g of SO3

Mass of SO3 required to produce 49% of 400 g H2SO4 = 326.5 × 49% = 160 g

Therefore, 160 g of SO3 are needed to make 400 g of 49% H2SO4.

Learn more about mass and moles at: brainly.com/question/15374113

#SPJ1

7 0

2 years ago

Can liquid CO2 exist on Earth? Why or Why not ?

Zanzabum

I uploaded the answer to a file hosting. Here's link:

tinyurl.com/wpazsebu

6 0

3 years ago

What is the osmotic pressure of a 100 ml of toluene solution that contains a total of 0.005 moles of a polymer dissolved in it a

allsm [11]

Osmotic pressure is the pressure that would have to be applied to a pure solvent to prevent it from passing into a given solution by osmosis.

That can be mathematical computed from the expression:

Osmotic pressure=C×R×T

Where,

C= Concentration

R=Gas constant

T=Temperature

Concentration=Number of moles of solute/Volume(L)

=0.005*1000/100

=0.05

R= 0.08206 atm L/mol K

T=25+273

=298

Osmotic pressure= 0.05×0.08206×298

=1.2 atm

4 0

3 years ago

a 0.555 g sample of mayonnase was burned in excess oxygen inside a bomb calorimeter with a total heat capacity (bomb and water)

Fofino [41]

Answer:

$Dietary\ Calories=65.6kcal$

Explanation:

Hello!

In this case, since we can see that the heat released by the combustion of the mayonnaise is absorbed by the bomb calorimeter and water, we can set up the following equation:

$m_{mayonnaise}q_{mayonnaise}=C\Delta T$

Whereas q for mayonnaise stands for the heat due to its usage; thus, we plug in to obtain:

$q_{mayonnaise}=\frac{5.20kJ/\°C*2.93\°C}{0.555g} \\\\q_{mayonnaise}=27.45\frac{kJ}{g}$

Now, if 10.0 g are eaten, the energy provided by it turns out:

$E_{mayonnaise}=27.45kJ/g*10.0g\\\\E_{mayonnaise}=274.5kJ$

And we need that value in dietary calories, 1 kcal:

$Dietary\ Calories=274.52kJ*\frac{1kcal}{4.184kJ}\\\\ Dietary\ Calories=65.6kcal$

Best regards!

4 0

3 years ago