Answer:
mass 1.25 Liters NH₃(gas) = 0.949 grams (3 sig-figs)
Explanation:
At STP (Standard Temperature-Pressure conditions => 0°C(=273K) and 1atm pressure, 1 mole <u>any</u> gas will occupy 22.4 Liters.
So, given 1.25 Liters ammonia gas at STP, convert to moles then multiply by formula wt. (17g/mole gives mass of NH₃.
moles NH₃(gas) = 1.25L NH₃(gas)/22.4L NH₄(gas)· NH₃(gas)mole⁻¹ = 0.0558 mole NH₃(gas).
Converting to grams NH₃(gas) = 0.0558 mole NH₃(gas) x 17 g·mol⁻¹ = 0.949 grams NH₃(gas).
Based on the calculations, the mass of Aluminum in 4.85 × 10²² atoms is equal to 2.1762 grams.
<h3>How to calculate the mass of Aluminum?</h3>
In order to determine the mass of Aluminum, we would calculate the number of atoms in 1 mole of an Aluminum atom in accordance with Avogadro's constant.
1 mole of Aluminum atom = 6.02 × 10²³ molecules
X moles of Aluminum atom = 4.85 × 10²² molecules
Cross-multiplying, we have:
X = 4.85 × 10²²/6.02 × 10²³
X = 0.0806 moles.
Mass = Molar mass × Number of moles
Mass = 27 × 0.0806
Mass = 2.1762 grams.
Read more on moles here: brainly.com/question/3173452
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Answer:
Explanation:
Which of the following elements would lose an electron easily?
In particular, cesium (Cs) can give up its valence electron more easily than can lithium (Li). In fact, for the alkali metals (the elements in Group 1), the ease of giving up an electron varies as follows: Cs > Rb > K > Na > Li with Cs the most likely, and Li the least likely, to lose an electron
