All categories

2 years ago

Complete the linear function rule for the line that passes through the points of the ordered pairs listed in the table.

Mathematics

1 answer:

koban [17]2 years ago

8 0

Answer:

y = 3x + 4

Step-by-step explanation:

All that is missing is the rate of change [slope], so find it:

-y₁ + y₂\-x₁ + x₂ = m

$\frac{-4 - 5}{0 - 3} = \frac{-9}{-3} = 3$

I am joyous to assist you anytime.

You might be interested in

A group of biologists found a total of 15 loggerhead turtle nests along a beach during a certain season. This was 20% of the tot

Andre45 [30]

20% also equals 1/5, right?

So in order to find the total number of turtle nests, just find 5/5, or multiply 15 by 5.

15 x 5 = 75

There were 75 total nests

6 0

2 years ago

Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16

IrinaK [193]

Answer:

Jogging 6th time.

Step-by-step explanation:

We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.

We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.

We know that an arithmetic sequence is in form $a_n=a_1+(n-1)d$ , where,

$a_n$ = nth term of sequence,

$a_1$ = 1st term of sequence,

n = Number of terms in sequence,

d = Common difference.

Let us find common difference of our given sequence as:

$\frac{3}{8}-\frac{3}{16}\Rightarrow \frac{6}{16}-\frac{3}{16}=\frac{3}{16}$

Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.

$1$

Let us solve for n.

$1$

$1\cdot \frac{16}{3}$

$5.333$

$n>5.333$

We can also write next terms of our sequence as:

$\frac{3}{16},\frac{6}{16}, \frac{9}{16},\frac{12}{16},\frac{15}{16},\frac{18}{16}$

Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.

7 0

2 years ago

If w varies inversely with the square root of t and w = 5 when t = 49,

VARVARA [1.3K]

Answer:

x=k/y

w=k/t

5=k/√49

5=k/7

k=5×7

k=35

5 0

2 years ago

A cell phone manufacturer claims that the average battery life of its newest flagship smartphone is exactly 20 hours. Javier bel

adelina 88 [10]

Answer:

(B) Fail to reject the null hypothesis that the true population mean battery life of the smartphone is equal to 20 hours.

(C) There is not enough evidence at the α=0.05 level of significance to suggest that the true population mean battery life of the smartphone is less than 20 hours.

Step-by-step explanation:

1) Data given and notation

$\bar X=19.5$ represent the battery life sample mean

$s=1.9$ represent the sample standard deviation

$n=33$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean battery life is less than 20 :

Null hypothesis: $\mu \geq 20$

Alternative hypothesis: $\mu < 20$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{19.5-20}{\frac{1.9}{\sqrt{33}}}=-1.51$

4) P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=33-1=32$

Since is a one-side lower test the p value would be:

$p_v =P(t_{(32)}$

5) Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the average battery life it's not significantly different less than 20 hours at 5% of signficance. If we analyze the options given we have:

(A) Reject the null hypothesis that the true population mean battery life of the smartphone is equal to 20 hours. FALSE, we FAIL to reject the null hypothesis.

(B) Fail to reject the null hypothesis that the true population mean battery life of the smartphone is equal to 20 hours. TRUE, we fail to reject the null hypothesis that the mean would be 20 or higher .

(C) There is not enough evidence at the α=0.05 level of significance to suggest that the true population mean battery life of the smartphone is less than 20 hours. TRUE, we FAIL to reject the null hypothesis that the mean is greater or equal to 20 hours, so we reject the alternative hypothesis that the mean is less than 20 hours.

(D) There is enough evidence at the α=0.05 level of significance to support the claim that the true population mean battery life of the smartphone is not equal to 20 hours. FALSE the claim is not that the mean is different from 20. The real claim is: "Javier believes the mean battery life is less than 20 hours".

5 0

2 years ago

Use the rational zeroes theorem to state all the possible zeroes of the following polynomial:

Mkey [24]

Answer:

All the possible zeroes of the polynomial: f(x) = $3x^{6} + 4x^{3} - 2x^{2} +4$ are ±1 , ±2 , ±4 , ± $\frac{1}{3}$ , ± $\frac{2}{3}$ , ± $\frac{4}{3}$ by using rational zeroes theorem.

Step-by-step explanation:

Rational zeroes theorem gives the possible roots of polynomial f(x) by taking ratio of p and q where p is a factor of constant term and q is a factor of the leading coefficient.

The polynomial f(x) = $3x^{6} + 4x^{3} - 2x^{2} +4$

Find all factors (p) of the constant term.

Here we are looking for the factors of 4, which are:

±1 , ±2 and ±4

Now find all factors (q) of the coefficient of the leading term

we are looking for the factors of 3, which are:

±1 and ±3

List all possible combinations of ± $\frac{p}{q}$ as the possible zeros of the polynomial.

Thus, we have ±1 , ±2 , ±4 , ± $\frac{1}{3}$ , ± $\frac{2}{3}$ , ± $\frac{4}{3}$ as the possible zeros of the polynomial

Simplify the list to remove and repeated elements.

All the possible zeroes of the polynomial: f(x) = $3x^{6} + 4x^{3} - 2x^{2} +4$ are ±1 , ±2 , ±4 , ± $\frac{1}{3}$ , ± $\frac{2}{3}$ , ± $\frac{4}{3}$

Learn more about Rational zeroes theorem here -https://brainly.ph/question/24649641

#SPJ10

7 0

1 year ago