Answer:
The interquartile range is 5.
Step-by-step explanation:
Ah, a throwback to interquartile range... let me help :)
4,5,6,8,9,10,11,12
First, you need to know how to use the IQR. The interquartile range is basically known as the process of subtracting the upper quartile and the lower quartile of a set of data. The lower quartile should be written as Q1, and the upper quartile would be labeled as Q3. This would make the midpoint (median) data set Q2, and the highest possible point would be labeled Q4. Next, you have to always understand what you are looking at. For example, let's split the set 5,6,7,8,9,10,11,12 into groups. 5 and 6 would be Q1, 7 and 8 would be Q2, 9 and 10 would be Q3, and last but not least, 11 and 12 would be labeled as Q4. Now take Q1 and subtract it from Q3 and that is how you get your IQR.
Answer:
Well, it's the perimeter, so...40.
You just calculate the perimeter of a rectangle with the lenght of 12 and width of 8, by the formula

or you can factor it out.
Answer:
Equation is cut out
Step-by-step explanation:
Upload a clear picture
Answer:
8(3j-2)
Step-by-step explanation:
If M is the midpoint of PQ, then PM and MQ are equal.
As PM and MQ are given , equal them to each other to solve for x.
7x+8=5x+20
Subtract 5x on both sides to get 2x+8=20
Subtract 8 on both sides to get 2x=12
divide by 2 on both sides to get x=6
Use the value of x=6 and plug it into the equations for PM and MQ to find their value.
PM=7x+8
=7(6) 8 =42 + 8 = 50
(you can already tell MQ is also 50 as PM and MQ are equal, but we still solve for MQ just for the fun of it)
MQ=5x + 20
=5(6) +20=30+20=50
PM=50
MQ=50
PQ= PM + MQ= 50 + 50 = 100
Have a great night.