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3 years ago

How do you write 5,002,190 in expanded form

2 answers:

5 0

Answer:In this question, you are given a number in the standard form and asked to convert it into expanded form. In expanded form, you need to expand it to every digit that has value(all that wasn't 0).

Step-by-step explanation:

Anarel [89]3 years ago

3 0

5,000,000 + 2,000 + 100 + 90

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17.2/3
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3 years ago

The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s

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4 years ago

slope-intercept form for the line that passes through (-1,-7) and is perpendicular to the graph of 3x+12y=-6

Mrac [35]

Answer:

Step-by-step explanation:

We first need to find the slope of the given line. Putting that standard form of a line into slope intercept:

12y = -3x - 6 so

$y=-\frac{1}{4}x-\frac{1}{2}$

In this form we can easily determine that our slope is -1/4. That means that the perpendicular slope, the opposite reciprocal, is +4. We will write first the point slope of the new line using our given point, then solve it for y, putting it into slope-intercept form. y - (-7) = 4(x - (-1)) and

y + 7 = 4x + 4 so

y = 4x + 4 - 7 so

y = 4x - 3

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3 years ago

Kirk is taking an exam and has 1 1/2 hours to complete the test. He has used 1/3 of his time already. How much time has Kirk use

maks197457 [2]

Answer:

30 minutes!!!!

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3 years ago

Read 2 more answers

Suppose that the distribution of typing speed in words per minute (wpm) for experienced typists using a new type of split keyboa

KengaRu [80]

Answer:

a. 0.5 or 50%

b. 0.496 or 49.6%

c. 0.8185 or 81.85%

d. Yes, it would be just 0.0013 or 0.13% of probability to find a typist whose speed exceeds 105 wpm

e. 0.0252 or 2.52%

f. The qualifying speed would be 47.4 wpm.

Step-by-step explanation:

a. Let's find the z-score this way:

μ = 60 σ= 15

z-score = (x - μ)/σ

z-score = (60 - 60)/15

z-score = 0

Now, let's calculate the p value for z-score = 0, using the z-table:

p (z=0) = 0.5 or 50%

b. z-score = (x - μ)/σ

z-score = (59.9 - 60)/15

z-score = -0.01

Now, let's calculate the p value for z-score = -.0.01, using the z-table:

p (z = -0.01) = 0.496 or 49.6%

If the question were less or equal than 60, a and b would have the same answer. But in this case, the question is "less than 60 wpm".

z-score = (x - μ)/σ

z-score = (45 - 60)/15

z-score = - 1

Now, let's calculate the p value for z-score = -1, using the z-table:

p (z = -1) = 0.1587

z-score = (x - μ)/σ

z-score = (90 - 60)/15

z-score = 2

Now, let's calculate the p value for z-score = 2, using the z-table:

p (z = 2) = 0.9772

In consequence,

p (-1 ≤ z ≤ 2) = 0.9772 - 0.1587 = 0.8185 or 81.85%

d. z-score = (x - μ)/σ

z-score = (105 - 60)/15

z-score = 3

Now, let's calculate the p value for z-score = 3, using the z-table:

p (z = 3) = 0.9987

In consequence,

p (z > 3) = 1 - 0.9987 = 0.0013

Yes, it would be just a 0.13% of probability to find a typist whose speed exceeds 105 wpm.

e. z-score = (x - μ)/σ

z-score = (75 - 60)/15

z-score = 1

Now, let's calculate the p value for z-score = 1, using the z-table:

p (z = 1) = 0.8413

In consequence,

p (z > 1) = 1 - 0.8413 = 0.1587

and if the two typists are independently selected, then

p = 0.1587 * 0.1587

p = 0.0252 or 2.52%

f. p = 0.2, using the z-table, the z-score is -0.84, then:

z-score = (x - μ)/σ

-0.84 = (x - 60)/15

-12.6 = x - 60

-x = -60 + 12.6

-x = - 47.4

x = 47.4

The qualifying speed would be 47.4 wpm.

8 0

3 years ago