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Doss [256]
3 years ago
15

Choose the problem modeled by the picture. A) 1 3 × 3 2 = 3 6 B) 1 4 × 3 6 = 3 24 C) 3 4 × 1 6 = 3 24 D) 1 3 × 3 4 = 3 12

Mathematics
2 answers:
Morgarella [4.7K]3 years ago
3 0

Answer:  The answer is (C) 3 4 × 1 6 = 3 24


Step-by-step explanation:  We are given a rectangular picture made of square boxes and we are to find among the given options which is modelled by the given picture.

In the diagram, there are 6 boxes lengthwise and 4 boxes breadthwise. Also, 3 × 4 boxes are painted yellow and 1 × 6 boxes are painted blue. The common boxes will be 3.

Therefore, the correct choice is  3 4 × 1 6 = 3 24

Hence, (C) is the correct option.



allochka39001 [22]3 years ago
3 0

Answer:

Is it C 3/4 x 1/6 = 3/24

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Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both, in case
lozanna [386]

Answer:

0.3339 = 33.39% probability that both Dave and Mike will show up

Step-by-step explanation:

Probability of independent events:

If A and B are independent events, the probability of both happening at the same time is given by:

P(A \cap B) = P(A)P(B)

In this question:

Event A: Dave shows up.

Event B: Mike shows up.

Christine knows that there is a 47% chance that Dave will not show up and a 37% chance that Mike will not show up.

This means that P(A) = 1 - 0.47 = 0.53, P(B) = 1 - 0.37 = 0.63.

a. What is the probability that both Dave and Mike will show up

P(A \cap B) = P(A)P(B) = 0.53*0.63 = 0.3339

0.3339 = 33.39% probability that both Dave and Mike will show up

8 0
2 years ago
What is the solution of the proportion? 14/12 = D/48<br> a. 56<br> b. 672<br> c. 168<br> d. 576
Verdich [7]
So basically we can simplify the fraction by finding the gcf which is the greatest common factor so 14/12 both have 2 in common we simplify that by dividing by 2 so 14÷2 is 7/6 is the fraction on the left hand side and d/48 is the fraction on the right hand side so to solve for d we have to divide 336/6 whixh equals 56 as tour answer. Hoped this helped!!
8 0
3 years ago
Read 2 more answers
Quadrilateral ABCD is inscribed in a circle. What is the measure of angle A? Enter your answer in the box.
SashulF [63]

Answer:

135°

Step-by-step Explanation:

==>Given:

An inscribed quadrilateral ABCD with,

m<A = (3x +6)°

m<C = (x + 2)°

==>Required:

measure of angle A

==>Solution:

First, let's find the value of x.

Recall that the opposite angles in any inscribed quadrilateral in a circle are supplementary.

Therefore, this means m<A + m<C = 180°

Thus, (3x+6) + (x+2} = 180

3x + 6 + x + 2 = 180

Collect like terms:

3x + x + 6 + 2 = 180

4x + 8 = 180

Subtract 8 from both sides:

4x + 8 - 8 = 180 - 8

4x = 172

Divide both sides by 4:

4x/4 = 172/4

x = 43

We can now find m<A = (3x + 6)°

m<A = 3(43) + 6

= 129 + 6

measure of angle A = 135°

6 0
3 years ago
Given f'(x)=(x-4)(6-2x) find the x-coordinate for the relative minimum of the graph f(x).
vlabodo [156]
<span>The graph you plotted is the graph of f ' (x) and NOT f(x) itself. </span>

Draw a number line. On the number line plot x = 3 and x = 4. These values make f ' (x) equal to zero. Pick a value to the left of x = 3, say x = 0. Plug in x = 0 into the derivative function to get

f ' (x) = (x-4)(6-2x)
f ' (0) = (0-4)(6-2*0)
f ' (0) = -24

So the function is decreasing on the interval to the left of x = 3. Now plug in a value between 3 and 4, say x = 3.5

<span>f ' (x) = (x-4)(6-2x)
</span><span>f ' (3.5) = (3.5-4)(6-2*3.5)
</span>f ' (3.5) = 0.5

The function is increasing on the interval 3 < x < 4. The junction where it changes from decreasing to increasing is at x = 3. This is where the min happens.

So the final answer is C) 3
5 0
3 years ago
Help please thank you so much
krok68 [10]
Alright, so since 20/100=1/5, and 1/5 of 45=9, 20% off of 45=9 and 45-9=36 dollar sale. Since 30=30/100, we can divide 95 by 100 and multiply that by 30 to get 0.95*30=28.5. 95-28.5=66.5

Next, we need to find 8% of 36+66.5=102.5. 8=8/100, so we divide 102.5 by 100 and multiply it by 8, getting 1.025*8=8.2
6 0
3 years ago
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