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Doss [256]
3 years ago
15

Choose the problem modeled by the picture. A) 1 3 × 3 2 = 3 6 B) 1 4 × 3 6 = 3 24 C) 3 4 × 1 6 = 3 24 D) 1 3 × 3 4 = 3 12

Mathematics
2 answers:
Morgarella [4.7K]3 years ago
3 0

Answer:  The answer is (C) 3 4 × 1 6 = 3 24


Step-by-step explanation:  We are given a rectangular picture made of square boxes and we are to find among the given options which is modelled by the given picture.

In the diagram, there are 6 boxes lengthwise and 4 boxes breadthwise. Also, 3 × 4 boxes are painted yellow and 1 × 6 boxes are painted blue. The common boxes will be 3.

Therefore, the correct choice is  3 4 × 1 6 = 3 24

Hence, (C) is the correct option.



allochka39001 [22]3 years ago
3 0

Answer:

Is it C 3/4 x 1/6 = 3/24

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The mult of 5-6 to the power of 76
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Encuentra el promedio,mediana,moda y rango de los siguientes datos: 14,16,21,25,16,12,18,17,19
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8 0
2 years ago
Question #7
Sever21 [200]

Answer:

The area is 56.7 square inches

Step-by-step explanation:

Given

See attachment for corner shelf

Required

The area

The corner shelf is a quadrant with radius;

r = 8.5in

The area of a quadrant is:

Area = \frac{\pi r^2}{4}

So, the area of the corner shelf is:

Area = \frac{\pi * 8.5^2}{4}

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7 0
3 years ago
Determine the coordinates of the intersection of the diagonals of square ABCD with verticals A(-4,6), B(5,6) C(4,-2), and D(-5,-
timama [110]

Given:

Vertices of a square are A(-4,6), B(5,6) C(4,-2), and D(-5,-2).

To find:

The intersection of the diagonals of square ABCD.

Solution:

We know that diagonals of a square always bisect each other. It means intersection of the diagonals of square is the midpoint of diagonals.

In the square ABCD, AC and BD are two diagonals. So, intersection of the diagonals is the midpoint of both AC and BD.

We can find midpoint of either AC or BD because both will result the same.

Midpoint of A(-4,6) and C(4,-2) is

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Midpoint=\left(\dfrac{-4+4}{2},\dfrac{6+(-2)}{2}\right)

Midpoint=\left(\dfrac{0}{2},\dfrac{6-2}{2}\right)

Midpoint=\left(\dfrac{0}{2},\dfrac{4}{2}\right)

Midpoint=\left(0,2\right)

Therefore, the intersection of the diagonals of square ABCD is (0,2).

4 0
3 years ago
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