M∥n, m∠1 = 50°, m∠2 = 48°, and line s bisects ∠ABC. What is m∠3?
2 answers:
Answer
m<3 = 49°
Step-by-step explanation:
It is given that,
M∥n, m∠1 = 50°, m∠2 = 48°, and line s bisects ∠ABC
m<DEF = m<1 + m<2 = 50° + 48° = 98°
Corresponding angle of <DEF is equal to <ABC = 98°
To find m<3
< 4 = <5 = 98/2 = 49° (Since line s bisects ∠ABC)
Therefore,
m<3 = 49° (< 4 and <3 are vertically opposite angles)
<u>Answer: </u>
m∠3 = 49°
<u>Step-by-step explanation: </u>
We are given that the angles m∠1 = 50° and m∠2 = 48° and the line s bisects ∠ABC.
If m∠1 = 50° and m∠2 = 48°, then ∠DEF = 50 + 48 = 98°
So ∠DEB will be equal to = 180 - 98 = 82°
If ∠DEB = 82°, then the angle from A to B will 180 - 82 = 98°.
We know that the line s bisects ∠ABC, therefore the measure of angle m∠3 will be half of 98 = 49 °
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