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FrozenT [24]
3 years ago
6

M∥n, m∠1 = 50°, m∠2 = 48°, and line s bisects ∠ABC. What is m∠3?

Mathematics
2 answers:
Nutka1998 [239]3 years ago
5 0

Answer

m<3  = 49°

Step-by-step explanation:

It is given that,


M∥n, m∠1 = 50°, m∠2 = 48°, and line s bisects ∠ABC


m<DEF = m<1 + m<2 = 50° + 48° = 98°


Corresponding angle of <DEF is equal to <ABC = 98°


To find m<3


< 4 = <5 = 98/2 = 49° (Since line s bisects ∠ABC)


Therefore,

m<3 = 49°  (< 4 and <3 are vertically opposite angles)



Sindrei [870]3 years ago
5 0

<u>Answer:</u>

m∠3 = 49°

<u>Step-by-step explanation:</u>

We are given that the angles m∠1 = 50° and m∠2 = 48° and the line s bisects ∠ABC.

If m∠1 = 50° and m∠2 = 48°, then ∠DEF = 50 + 48 = 98°

So ∠DEB will be equal to = 180 - 98 = 82°

If ∠DEB = 82°, then the angle from A to B will 180 - 82 = 98°.

We know that the line s bisects ∠ABC, therefore the measure of angle m∠3 will be half of 98 = 49°

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