For there to be 1 car, we consider two possible outcomes:
The first door opened has a car or the second door opened has a car.
P(1 car) = 2/6 x 4/5 + 4/6 x 2/5
P(1 car) = 8/15
For there to be no car in either door
P(no car) = 4/6 x 3/5
P(no car) = 2/5
Probability of at least one car is the sum of the probability of one car and probability of two cars:
P(2 cars) = 2/6 x 1/5
= 1/15
P(1 car) + P(2 cars) = 8/15 + 1/15
= 3/5
Answer: there were 12 chocolates in each box. (Originally, before any got eaten)
Step-by-step explanation: let x represent the total amount of chocolates in each box.
8x - 3(8) = 72
8x - 24 = 72 add 24 to both sides
8x = 96 divide both sides by 8
X = 12
Answer:
- 1.5
Step-by-step explanation:
put two x variables in one place and two numbers in one place
28x- 22x = 56-65
6x = -9
x=-1.5
Answer:
it's −32
Step-by-step explanation:
my bad if u get it wrong or anything
Step-by-step explanation:
Can you please reword your problem
