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nordsb [41]
3 years ago
14

A researcher surveyed 150 high school students and found that 68% played a musical insturment. What would be a reasonable range

for the population mean?
Mathematics
1 answer:
maria [59]3 years ago
5 0

Answer:

The reasonable range for the population mean is (61%, 75%).

Step-by-step explanation:

The interval estimate of a population parameter is an interval of values that consist of the values within which the true value of the parameter lies with a certain probability.

The mean of the sampling distribution of sample proportion is, \hat p.

One of the best interval estimate of population proportion is the 95% confidence interval for proportion,

CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

Given:

n = 150

\hat p = 0.68

The critical value of <em>z</em> for 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the 95% confidence interval for proportion as follows:

CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

     =0.68\pm1.96\sqrt{\frac{0.68(1-0.68)}{150}}\\\\=0.68\pm 0.0747\\\\=(0.6053, 0.7547)\\\\\approx (0.61, 0.75)

Thus, the reasonable range for the population mean is (61%, 75%).

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Answer:

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Step-by-step explanation:

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From the given graph it is clear that the graph of function intersect x-axis at x=1 and touch the x-axis at x=-2.

It means (x-1) and (x+2) are not factors of given function but power of (x+2) must be 2.

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Therefore, the required function is f(x)=\dfrac{7}{20}(x+2)^2(x-1).

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3 years ago
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