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ra1l [238]
3 years ago
9

How do the expressions 4(3+x) and (3+3+3+3) + (x+x+x+x) compare to one another

Mathematics
2 answers:
valina [46]3 years ago
6 0

Answer:

Well they represent the same answer as the second expression is the distributive property of the first expression.

Step-by-step explanation:

4(3+x) is basically 4 • (3+x)since we are working with addition and multiplication you can use the distributive property. That can be written out as (4•3) + (4•x). If you wanted to simplify it even more then it could be written as (3+3+3+3) + (x+x+x+x)

Dafna1 [17]3 years ago
3 0

Answer:

Step-by-step explanation:

If we expand 4(3+x), we get (4*3)+(4*x).

Then we do 4*3 to get 12 and 4*x to get 4x

(3+3+3+3) is the same thing as 4*3, because we are adding 3 together 4 times. (3+3+3+3) gives us 12 as well, since they are the same thing.

(x+x+x+x) is the same thing because we are adding x together 4 times, which is the same thing as (4*x). (x+x+x+x) gives us 4x as well.

Hope this helps.

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How can one halfx − 5 = one thirdx + 6 be set up as a system of equations? 2y + x = −10 3y + x = 18 2y + 2x = −10 3y + 3x = 18 2
Doss [256]

Answer:

2y-x= -10

3y-x = 18

Step-by-step explanation:

The correct option is . 2y-x = -10 ,  3y-x = 18

one half x − 5 = 1/2 (x-5)

one third x + 6 = 1/3 *(x+6)

1/2 x-5 = 1/3x+6 =y

y= 1/2x-5

y = 1/3x+6

Now,

y=x/2 -5     equation 1

y = x/3 +6    equation 2

By taking L.C.M of the first equation we get:

y=x/2 -5

y= x-10/2

Now multiply both terms by 2.

2y=x-10

2y-x= -10

Now lets solve second equation:

Take L.C.M of the second equation:

y = x/3 +6

y=x+18/3

Multiply both sides by 3

3y= x+18

3y-x = 18

Therefore the system of equations we get is:

2y-x= -10

3y-x = 18 ....

4 0
3 years ago
Y=7e^6x -5x^3 + 30 find Y
WARRIOR [948]

Answer:

reorder 7e^6x and -5x^3

y=-5x^3 +7e^6x +3e

Step-by-step explanation:

Now thats if its 7e to the power of 6x

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3 years ago
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