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ehidna [41]
3 years ago
12

2 candy bars cost $.98 at this rate how much do 5 candy bars cost? I NEED ASAP

Mathematics
1 answer:
alisha [4.7K]3 years ago
7 0

Answer:

2.45$

Step-by-step explanation:

98/2 =49

49x5 equals 2.45

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Three-fifths of the members of the Spanish club are girls. There are a total of 30 girls in the Spanish club.
erastova [34]

Problem: You do not have an attached picture. Though, I can help you out with this question.

So, three-fifths of the members are girls. There are 30 of girls. We can immediately make an equation using "x".

3/5x=30

3/5x × 5/3=30 × 5/3

x=50

Thus, there are 50 members in total. Though if x is too hard for you, you may substitute it by using another variable.

Variable in here is x.

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3 years ago
11. If a square has an area of 121 square meters, what is the side length? A. 60.5 m B. 12 m C. 11 m D. 484 m​
butalik [34]

Answc

Step-by-step explanation:

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What value is equivalent to 34 − 23⋅ (5 − 2) − 60 ?
xxMikexx [17]

Answer:

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Step-by-step explanation:

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3 years ago
Look at the graph below measuring the speed of a truck and answers the following 2 question.
NemiM [27]
X would be equal to time and y be equal to distance

The y axis would be measuring distance and the x axis would be measuring time. Another name for a speed graph is the distance time graph. The y axis would be measuring the distance covered by the truck in meters and the x axis would be for the time it takes to reach that distance in second.



B) 2-6 would represent contact motion, meaning the vehicle is at rest. The time would be increasing from 2-6 to however the distance remains the same which is 20m
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Solve the simultaneous equation y-2x+1=0 and 4x^2+3y^2-2xy=7
Lapatulllka [165]

The first equation is y-2x+1=0

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The second equation is 4x^{2}+3y^{2}-2xy=7 (Equation 2)

Putting the value of x from equation 1 in equation 2.

we get,

4x^{2}+3(2x-1)^{2}-2x(2x-1)=7

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by simplifying the given equation,

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D=b^{2}-4ac

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Now the formula for solution 'x' of quadratic equation is given by:

x=\frac{-b+\sqrt{D}}{2a}  and  x=\frac{-b-\sqrt{D}}{2a}

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Hence, these are the required solutions.

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