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storchak [24]
3 years ago
15

A triangle T is bounded (on three sides) by the lines x = 6, y = 0, and y = 3 2 x. A rectangle of width w is inscribed inside T.

Find the area of this rectangle.

Mathematics
1 answer:
Viktor [21]3 years ago
7 0

Answer:

33.85 units^2

Step-by-step explanation:

you must first draw the triangle on the plane using the equations (see

attached file), you will have a right angle triangle with a height of 192 and a base of 6.

then you calculate the angle with the tangent function = 88.21

Then you use the small triangle to find the value of a (see attached file).

Finally, you propose an equation for X to find one of the sides of the triangle, once you have x squared it, and you already have the area,

i attached procedure

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Monica [59]

4i

i=\sqrt{-1}

\sqrt{-16}=\sqrt{-1}*4

\sqrt{-16}=i*4

4i

Hope this helps.

頑張って!

8 0
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Vlad1618 [11]

Answer:

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Goryan [66]

Answer:

1

Step-by-step explanation:

The given expression is

\frac{2^{\frac{11}{2} }\times 2^{-7}\times 2^{-5}}{2^3\times 2^{\frac{1}{2} }\times 2^{-10}}

Recall and use

a^m\times a^n=a^{m+n}

\frac{2^{\frac{11}{2} -7-5}}{ 2^{3+\frac{1}{2} -10}}

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8 0
3 years ago
Geometry: The Expression 15×x×6 represents the volume of a rectangular prism with a length of 15, a width of x, and a height of
ziro4ka [17]

Step-by-step explanation:

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3 0
3 years ago
Which of the following graphs shows a pair of lines that represents the equations with the solution (3, −6)? (1 point)
GREYUIT [131]

Given:

The solution of two equation is (3,-6).

To find:

The graphs that shows a pair of lines that represents the equations with the solution (3, −6).

Solution:

In first graph, both line intersect each other at point (-6,3). So, the solution of the pair of lines is (-6,3).

In second graph, both line intersect each other at point (-3,6). So, the solution of the pair of lines is (-3,6).

In third graph, both line intersect each other at point (3,-6). So, the solution of the pair of lines is (3,-6).

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Therefore, the correct option is C.

7 0
3 years ago
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