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vlada-n [284]
3 years ago
8

Shop only had 2 types of stamps left using

Mathematics
1 answer:
saveliy_v [14]3 years ago
7 0

Answer:

  {3¢, 28¢} or {4¢, 19¢} or {7¢, 10¢}

Step-by-step explanation:

54 = 1×54 = 2×27 = 3×18 = 6×9

Possible values of the stamps are 1 more than the values of a pair of factors. Of course, a 2¢ and 55¢ stamp will not permit paying 54¢ in postage, so that combination won't work. However, other pairs that will work are ...

  • 3¢ and 28¢
  • 4¢ and 19¢
  • 7¢ and 10¢

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3 years ago
Given a mean of 61.2 and a standard deviation of 21.4, what is the z-score of the value 45 rounded to the nearest tenth?0.8−0.90
kherson [118]

Given: Mean μ = 61.2 and standard deviation σ =21.4

The Z score of the value x=45 is given by

Z = \frac{x - mean}{standard deviation}

Z = \frac{45 - 61.2 }{21.4}

Z = \frac{-16.2}{21.4}

Z = -0.757

The z-score value for 45 rounded to nearest tenth is -0.8

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3 years ago
How is (8×10,000)+(4×10)+(5×0.01)+(2×1) in standard form?
LUCKY_DIMON [66]

Eight x ten thousand plus four plus ten plus 5 times zero point zero one plus 2 times 1 Lol

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3 years ago
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Irina-Kira [14]

Answer:

10= d r = 5

2×3.14×5= 31.4 inches!

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2 years ago
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.In the Star Wars franchise, Yoda stands at only 66 centimeters tall. Suppose you want to see whether or not hobbits from the Lo
r-ruslan [8.4K]

Answer:

We conclude that the average height of hobbit is taller than Yoda.

Step-by-step explanation:

We are given that in the Star Wars franchise, Yoda stands at only 66 centimetres tall.

From a sample of 7 hobbits, you find their mean height \bar X = 80 cm with standard deviation s = 10.8 cm.

<u><em /></u>

<u><em>Let </em></u>\mu<u><em> = average height of hobbit.</em></u>

So, Null Hypothesis, H_0 : \mu \leq 66 cm      {means that the average height of hobbit is shorter than or equal to Yoda}

Alternate Hypothesis, H_A : \mu > 66 cm      {means that the average height of hobbit is taller than Yoda}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about population standard deviation;

                     T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n}}}  ~ t_n_-_1

where, \bar X = sample mean height = 80 cm

             s = sample standard deviation = 10.8 cm

             n = sample of hobbits = 7

So, <u><em>test statistics</em></u>  =  \frac{80-66}{\frac{10.8}{\sqrt{7}}}  ~ t_6

                              =  3.429

The value of t test statistics is 3.429.

<em>Now, at 0.01 significance level the t table gives critical value of 3.143 for right-tailed test. Since our test statistics is more than the critical value of t as 3.429 > 3.143, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis</u></em><em>.</em>

<em />

Therefore, we conclude that the average height of hobbit is taller than Yoda.

3 0
3 years ago
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