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marusya05 [52]
3 years ago
15

Plot the following two graphs on the same cartesian plain

Mathematics
1 answer:
gregori [183]3 years ago
4 0

The two functions are 1st degree polynomial, so they are both lines.

In order to draw a line, you have to sample two points and connect them.

To sample points from an equation, choose any value for x and compute the correspondent value for y.

For example, if we choose x=0 and x=1 for the first equation, we have

f(x)=3x-2 \implies f(0)=-2,\quad f(1)=1

So, the line passes through the points (0,-2) and (1,1)

Similarly, if we choose x=0 and x=3 for the first equation, we have

f^{-1}(x)=\dfrac{x}{3}+\dfrac{2}{3} \implies f(0)=\dfrac{2}{3},\quad f(3)=1

So, this line passes through the points \left(0,\frac{2}{3}\right) and (3,1)

If you draw the two points for each line and connect the pairs, you'll have the two lines.

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Step-by-step explanation:

Simplifying

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P is the centroid of XYZ. If XU = 57 what is PU? A. 38 B. 19 C. 28.5 D. 20​
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Given,

'p' is the centroid of \bigtriangleup XYZ and XU=57

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From Centroid Theorem we can write;

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