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3 years ago

Need help factoring this binomial: x^4-1?

2 answers:

8 0

So we notice that is the special factorization known as 'the difference of two perfect squares'
exg
a^2-b^2=(a-b)(a+b) so
x^4=(x^2)^2 and 1=1^2 so
(x^2)^2-(1)^2=(x^2-1)(x^2+1)

natima [27]3 years ago

5 0

Use the difference of squares factorization - that for any numbers a and b, (a-b)(a+b)=a^2-b^2.

We have:

(x^2+1)(x^2-1)=x^4-1

In addition:

(x-1)(x+1)=x^2-1, so we have:

(x^2+1)(x+1)(x-1)

As our complete factorization.

You might be interested in

How do you graph quadratic functions

NARA [144]

Answer:

you can plug it into a graphing calcuator right? or no

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Una heladeria dispone de 20 frutas distintas para elaborar sus malteadas. Si los clientes pueden elegir tres sabores para mezcla

Dahasolnce [82]

Answer:

Existen 6840 permitaciones de malteadas de tres sabores distintos que la heladería puede ofrecer.

Step-by-step explanation:

En este caso, el cliente que adquiere una malteada de tres sabores distintos sigue el siguiente procedimiento:

1) El primer sabor sale de cualquiera de las 20 frutas disponibles.

2) El segundo sabor es distinto al primer sabor, es decir, que sale de las 19 frutas restantes.

3) El tercer sabor es distinto al primer sabor y al segundo sabor, es decir, que sale de las 18 frutas restantes.

Puesto que existe una doble conjunción y que puede importar el orden según la preferencia del cliente, se habla matemáticamente de una permutación, definida como:

$n\mathbb{P}k = \frac{n!}{(n-k)!}$ (1)

Donde:

$n$ - Número de sabores disponibles, adimensional.

$k$ - Número de sabores escogidos, adimensional.

Si tenemos que $n = 20$ y $k = 3$ , entonces la cantidad de malteadas de tres sabores distintos es:

$n\mathbb{P}k = \frac{20!}{(20-3)!}$

$n\mathbb{P}k = \frac{20!}{17!}$

$n\mathbb{P}k = 20\cdot 19\cdot 18$

$n\mathbb{P}k = 6840$

Existen 6840 permitaciones de malteadas de tres sabores distintos que la heladería puede ofrecer.

5 0

3 years ago

Building a is 271 meters taller than building

kvv77 [185]

Let a and b represent the heights of the corresponding buildings (in meters).

... a = b +271 . . . . . . . a is 271 meters taller than b

... 2b -a = 211 . . . . . . if a is subtracted from twice b, the result is 211

Use the expression for a in the first equation to substitute for a in the second.

... 2b - (b+271) = 211

... b = 482 . . . . . . . . . . . simplify and add 271

... a = b +271 = 753

Building a is 753 meters tall; building b is 482 meters tall.

4 0

3 years ago

NEED HELP ASAP!!!

azamat

The answer is B f(x)= -3(x+1)^2+2

6 0

3 years ago

Please no wrong answers <br>what to do next??

Finger [1]

Step-by-step explanation:

I am not sure what you want to calculate as ultimate goal.

but your have an error already in your third line in the picture.

(3-6i)(2-4i) = 3×(2-4i) - 6i(2-4i)

you had there a "+" instead of a "-".

and then you made subsequent mistakes in every line, some of them are funnily bringing you more back to the real result (e.g. -12i + 12i would be 0 and not -24i, but if the third line would have been correct, then yes, -24i is actually needed) - but not completely.

= 3×2 - 3×4i - 6i×2 + 6i×4i =

= 6 - 12i - 12i + 24×-1 = 6 - 24i - 24 = -24i - 18

then in the last 3 lines you kind of lose it completely. I am absolutely not sure, what you are calculating, and where the "+" cube from instead of "×" (multiplications) and such.

(3+6i)(2+4i) = 3×2 + 3×4i + 6i×2 + 6i×4i =

= 6 + 12i + 12i + 24×-1 =

= 6 + 24i - 24 = 24i - 18

is that what you wanted to show ?

7 0

3 years ago