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UNO [17]
3 years ago
15

Which zero pair could be added to the function f(x)=x^2+12x+6 so that the function can be written in vertex form?

Mathematics
1 answer:
andrew11 [14]3 years ago
4 0
<span>f(x) = x</span>² <span>+ 12x + 6  </span>→ y = x² + 12x + 6<span>

Let us convert the standard form into vertex form.

1) Complete the squares. Isolate x</span>² and x terms.
<span>y - 6 = x</span>² + 12x
<span>
2) Create the perfect square trinomial. Whatever number is added on one side must also be added on the other side. 

y - 6 + 36 = x</span>² + 12x + 36<span>
y + 30 = (x + 6)</span>²
<span>y = (x + 6)</span>² - 30  ← Vertex form
<span>
To check:

y = (x + 6) (x + 6) - 30
y = x</span>² + 6x + 6x + 36 - 30
<span>y = x</span>² + 12x + 6<span>

The zero that could be added to the given function is 36, -36</span>
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What is the sum of 2.5 × 104 and 3.4 × 104? (1 point)
Tju [1.3M]

Answer:

5.9× 10^4

Step-by-step explanation:

I'm assuming that by "104" you actually meant "10^4," which reads "fourth power of 10."  Please be sure to use the symbol " ^ " to express exponentiation.

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or

5.9× 10^4

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3 years ago
Jayden and Sheridan both tried to find the missing side of the right triangle. A right triangle is shown. One leg is labeled as
agasfer [191]

Answer:

WOW that's tough to read all squished together!!!

Jayden and Sheridan both tried to find the missing side of the right triangle. A right triangle is shown. One leg is labeled as 7 centimeters. The hypotenuse is labeled as 13 centimeters.

Jayden's Work

Sheridan's Work

a2 + b2 = c2

a2 + b2 = c

272 + 132 = c272 + b2 = 132

49 + 169 = c

249 + b2 = 169

218 = c2b2 = 120

Square root 218 equals square root c squared.

Square root b squared equals  

square root 120.

14.76 ≈ cb ≈  

10.95Is either of them correct?  

***************************************************

In a right triangle

hypotenuse^2 = leg1 ^2 + leg2^2

13^2 = 7^2 + leg2^2

leg2^2 = 120

leg 2 = 10.9544511501

Basically, whoever said 10.95 is correct.

Step-by-step explanation:

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Solution to the system of equations
lara31 [8.8K]

Answer:

huh

Step-by-step explanation:

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