Given that plane P is parallel to the planes containing the base faces of the prism; then, if the plane meets the prism between the planes containing the hexagonal bases, then P meets the prism in a hexagonal region that is congruent (with the same size) to the bases of the prism.
Answer:
3
1 -----
25
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
× 
← factor the quadratic
= 
× ← cancel the factor (x - 7) and 6
= 
× 1
= 
slope = (y2 - y1)/(x2 - x1)
4/3 = (-3 - r)/(2 - 5)
4/3 = (-3 - r)/(-3)
-4 = -3 - r
-1 = -r
r = 1
