Answer:
A) 40/49
B) 36/42
Step-by-step explanation:
Given:
Red Balls, R : 4
White Balls, W : 3
Total Balls : 3+4=7 balls
A) If balls were replaced before the 2nd draw
P (White) = 3/7; P(Red) = 4
P(at least 1 red ball),
= 1 - P(no red balls)
= 1 - P(White, White)
= 1 - (3/7)(3/7)
= 1-(9/49)
= 40/49
A) If balls were replaced before the 2nd draw
P(1st White Ball) = 3/7 ; P(2nd White Ball) = 2/6
P(at least 1 red ball),
= 1 - P(no red balls)
= 1 - P(1st White, 2nd White)
= 1 - (3/7)(2/6)
= 1 - 6/42
= 36/42
