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3 years ago

How many parallel faces are shown

Mathematics

2 answers:

maksim [4K]3 years ago

6 0

Add more details such as a picture

Firdavs [7]3 years ago

4 0

Is this it or is there more to this question?

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Can you rewrite a sine as a cosine function and vice versa when describing a general sinusoidal graph? Explain.

tester [92]

Answer:

$sin(x+\frac{\pi}{2})=cos(x)$

$cos(x-\frac{\pi}{2})=sin(x)$

Step-by-step explanation:

* Lets explain how to solve the problem

- We can write a sine as a cosine by translate the sine function to the

left by $\frac{\pi}{2}$

- $sin(x+\frac{\pi}{2})=cos(x)$

∵ The value of sin(0 + π/2) = 1

∵ cos(0) = 1

∴ sin(0 + π/2) = cos(0)

∴ If sin(x) translated to the left by $\frac{\pi}{2}$ , then it will be

cos(x)

∴ $sin(x+\frac{\pi}{2})=cos(x)$

- Vice versa

- We can write a cosine as a sine by translate the cosine function to

the right by $\frac{\pi}{2}$

- $cos(x-\frac{\pi}{2})=sin(x)$

∵ The value of cos(0 - π/2) = 0

∵ sin(0) = 0

∴ cos(0 - π/2) = sin(0)

∴ If cos(x) translated to the right by $\frac{\pi}{2}$ , then it will be

sin(x)

∴ $cos(x-\frac{\pi}{2})=sin(x))$

- Look to the attached graphs for more understand

3 0

3 years ago

Use the given coordinates to determine if triangle ABC is congruent to triangle DEF.

AlladinOne [14]

We can find distances

Length of AB:

A=(-2,-2)

so, x1=-2 , y1=-2

B=(4,-2)

so, x2=4 , y2=-2

now, we can use distance formula

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

now, we can plug values

$AB=\sqrt{(4-(-2))^2+((-2)-(-2))^2}$

$AB=6$

Length of CB:

C=(4,6)

so, x1=4 , y1=6

B=(4,-2)

so, x2=4 , y2=-2

now, we can use distance formula

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

now, we can plug values

$CB=\sqrt{(4-(4))^2+((-2)-(6))^2}$

$CB=8$

Length of AC:

A=(-2,-2)

so, x1=-2 , y1=-2

C=(4,6)

so, x2=4 , y2=6

now, we can use distance formula

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

now, we can plug values

$AC=\sqrt{(4-(-2))^2+((6)-(-2))^2}$

$AC=10$

Length of DE:

D=(5,7)

so, x1=5 , y1=7

E=(5,1)

so, x2=5 , y2=1

now, we can use distance formula

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

now, we can plug values

$DE=\sqrt{(5-(5))^2+((1)-(7))^2}$

$DE=6$

Length of EF:

E=(5,1)

so, x1=5 , y1=1

F=(13,1)

so, x2=13 , y2=1

now, we can use distance formula

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

now, we can plug values

$EF=\sqrt{(13-(5))^2+((1)-(1))^2}$

$EF=8$

Length of DF:

D=(5,7)

so, x1=5 , y1=7

F=(13,1)

so, x2=13 , y2=1

now, we can use distance formula

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

now, we can plug values

$DF=\sqrt{(13-(5))^2+((1)-(7))^2}$

$DF=10$

now, we can compare them

$AB=DE=6$

$CB=EF=8$

$AC=DF=10$

now, we can draw both triangles

Since, sides of both triangles are equal

so, by using SSS rule

triangle ABC and triangle DEF are congruent

so, this is TRUE........Answer

3 0

3 years ago

How would you describe the plant’s growth over 6 weeks? Please help I will give you brainly!!!

AleksandrR [38]

Answer:

Increasing at a very fast rate.

8 0

3 years ago

Read 2 more answers

Please be right I can’t afford to get anymore wrong

Alex73 [517]

Answer:

dude its quizzits- its easy so hurry so you can get to 1st place or pick random-

Step-by-step explanation:

4 0

3 years ago

5.) 3x^2 - 13x + 4 = 0

Anna71 [15]

Answer:

Answer:

x= 1/3 or x=4

Step-by-step explanation:

Let's solve your equation step-by-step.

3x2−13x+4=0

Step 1: Factor left side of equation.

(3x−1)(x−4)=0

Step 2: Set factors equal to 0.

3x−1=0 or x−4=0

x= 1/3or x=4

plz give brainlyest

7 0

3 years ago