Well there can be two different solutions for this but i will choose the easier one. Obviously one requires a system of equations which obviously will involve a lot of thinking and some good algebra solving in order for them to solve.
So we can just keep adding the distance as we know they are in different directions. 49 + 65 = 114. So 114 * 4.5 = 513 miles. SO after around 4.5 hours they will be 513 miles apart.
<span>Let x = 0.5333333333 ...
So 100x = 53.3333333333 ...
and 10x = 5.3333333333 ...
---------------------------------
90x = 53 – 5 = 48.
So x = 48/90 = 8/15 after reduction to lowest terms (by factor of 6)
0.3333... = ⅓. and that 0.5 = ½.
So 0.533333... = 0.5 + 0.0333333...0.5 + 0.3333.../10 = 1/2 + (1/3)/10 = 1/2 + 1/30 = 16/30 = 8/15</span>
Im sure this means add because on a number line when you move to the right its adding. And since the amount of units were moving up by is 6 we would add 0+6 which equals 6.
4cm•2=8cm which is the length of the red paper so therefore Red paper= 4cmx8cm.
Then your going to take 3cm-4cm= 1cm
Next your going to solve for 7cm-8cm=1cm
Which leaves you with an answer of 1cmx1cm more of visible red paper.
Answer:
No Solutions.
Step-by-step explanation:
I will solve your system by substitution.
3y−3=3x; −3x+3y=−57
Step: Solve 3y−3=3x for y:
3y−3+3=3x+3 (Add 3 to both sides)
3y=3x+3
(3y/3=3x+3)/3
(Divide both sides by 3)
y=x+1
Step: Substitute x+1 for y in −3x+3y=−57:
−3x+3y=−57
−3x+3(x+1)=−57
3=−57 (Simplify both sides of the equation)
3+(−3)=−57+(−3) (Add -3 to both sides)
0=−60
