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Effectus [21]
3 years ago
8

Find the area of a circle whose radius is 52 km. Round to nearest tenth

Mathematics
2 answers:
kozerog [31]3 years ago
8 0

Step-by-step explanation:

3.142×52^2=8494.866535

8494.9 nearest tenth

goblinko [34]3 years ago
7 0

Answer:

8494.87 is the actual answer but the rounded version is 8494.9

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I need atleast 5 volunteers for the magic trick
Leto [7]

What magic trick??

Are you gonna do a magic??

Sorry for a lot of questions.

3 0
2 years ago
a piece of paper is 0.0075 in thick how many sheets of paper will be in a stack that is 2.25 inches high
boyakko [2]

Answer:

300

Step-by-step explanation:

That would be 2.25 / 0.0075

= 300

5 0
3 years ago
Let g(x) = 2x and h(x)= x^2 -4. find (g o h)(0)
finlep [7]
The answer is -8

====================================================

Explanation:

There are two ways to get this answer

Method 1 will have us plug x = 0 into h(x) to get
h(x) = x^2 - 4
h(0) = 0^2 - 4
h(0) = 0 - 4
h(0) = -4
Then this output is plugged into g(x) to get
g(x) = 2x
g(-4) = 2*(-4)
g(-4) = -8 which is the answer
This works because (g o h)(0) is the same as g(h(0)). Note how h(0) is replaced with -4
So effectively g(h(0)) = -8 which is the same as (g o h)(0) = -8

-----------------------

The second method involves a bit algebra first
Start with the outer function g(x). Then replace every x with h(x). On the right side, we will replace h(x) with x^2-4 because h(x) = x^2-4

g(x) = 2x
g(x) = 2( x )
g(h(x)) = 2( h(x) ) ... replace every x with h(x)
g(h(x)) = 2( x^2-4 ) ... replace h(x) on the right side with x^2-4
g(h(x)) = 2x^2-8
(g o h)(x) = 2x^2-8

Now plug in x = 0
(g o h)(x) = 2x^2-8
(g o h)(0) = 2(0)^2-8
(g o h)(0) = 2(0)-8
(g o h)(0) = 0-8
(g o h)(0) = -8

Regardless of which method you use, the answer is -8

5 0
3 years ago
How many factors does the following term have -9xyz
madreJ [45]

Answer:

4

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the length of side TS?
-Dominant- [34]
We know that

 in the triangle TQS
<span>applying the Pythagorean theorem
QS</span>²=TS²+TQ²---------> TQ²=QS²-TS²--------> TQ²=18²-9x²-----> equation 1

in the triangle TRS
TS²=TR²+RS²--------------> TR²=TS²-RS²-------> TR²=9x²-144----> equation 2

in the triangle QTR
TQ²=TR²+36-----------> equation 3


<span>I substitute 1 and 2 in 3
</span>18²-9x²=9x²-144+36--------> 18x²-432=0------> x²=24-------> x=√24
x=2√6
TS=3*x------> 3*2√6-----> 6√6
TS=6√6 units

the answer is
TS=6√6 units 
<span>6 is the square root of 6 units</span>
6 0
3 years ago
Read 2 more answers
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