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Katarina [22]
2 years ago
15

Simplify. 1/3(1−1/4)^2

Mathematics
1 answer:
xxMikexx [17]2 years ago
4 0
First step is parentheses so subtract 1/4 from 1

(1-1/4) = (4/4  - 1/4) = (3/4)

After parentheses we perform exponent operations

(3/4)^2 = (3^2/4^2) = (9/16)

Finally, after exponent operations we perform multiplications

(1/3)*(9/16) = (3/16)
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1000x8129 = 8,129,000

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3 years ago
A kite flier wondered how high her kite was flying. She used a protractor to measure an angle of 15∘ from level ground to the ki
Nataly [62]

Answer:

12.9 yd

Step-by-step explanation:

It helps if you draw a triangle. Draw a horizontal segment. That is the ground. Now at the left end start a new segment that goes up to the right at approximately 15 degrees until it its other endpoint directly above the right endpoint of the horizontal segment. Connect these two endpoints. The vertical side on the right shows the height of the kite. The hypotenuse is the string.

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6 0
2 years ago
The sides of a rhombus with angle of 60° are 6 inches. Find the area of the rhombus.
ehidna [41]
1. Check the drawing of the rhombus ABCD in the picture attached.

2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.

3. The diagonals:
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     ii) are perpendicular to each other, so m(DOC)=90°

4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.

5. By the pythagorean theorem, DO= \sqrt{ DC^{2}- OC^{2} }=  \sqrt{ 6^{2}- 3^{2} }=\sqrt{ 36- 9 }=\sqrt{ 27 }= \sqrt{9*3}= 
=\sqrt{9}* \sqrt{3} =3\sqrt{3}  (in)

6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*\frac{DO*OC}{2}=4 \frac{3 \sqrt{3} *3}{2}==2*9 \sqrt{3}=18 \sqrt{3} (in^{2})

6 0
3 years ago
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NISA [10]

Answer:

afb= 90

cfd= 62

Step-by-step explanation:

4 0
3 years ago
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