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White raven [17]
4 years ago
13

Find x such that 3^x = 27 mod 32 (b)

Mathematics
1 answer:
gregori [183]4 years ago
7 0

Answer:

The value of x is 11.

Step-by-step explanation:

Consider the provided information.

It is given that 3^x = 27 mod\ 32

We know that:

3^4=81

Now if we divide the number 81 with 32 it will gives us remainder 17.

This can be written as:

3^4\equiv 17(mod\ 32)

Now use the property: a^n\equiv b^n(mod\ m)

(3^4)^2\equiv 17^2(mod\ 32)

17²=289, if we divide 289 with 32 it will gives us remainder 1, thus.

3^8\equiv 1(mod\ 32)

Multiply both the sides by 3³.

3^8\times 3^3\equiv 3^3(mod\ 32)

3^{11}\equiv 27(mod\ 32)

Hence, the value of x is 11.

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Answer:

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Step-by-step explanation:

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Now in rounding up of numbers the dime is located one decimal place away i.e 0.5 in the number given in the problem statement

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since the number next to 5 is 9 and 9 is greater than 5 we will round up from 5 to 6

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Step-by-step explanation:

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