Question

Michael, Ronald, Lidia, Alexandra, and Catherine are sharing a basket of fries. The following table shows an incomplete probability model for who will eat the next fry. Person Probability Michael 0.30.30, point, 3 Ronald ??question mark Lidia 0.10.10, point, 1 Alexandra 0.320.320, point, 32 Catherine 0.10.10, point, 1 What is the probability that Ronald will eat the next fry?

Answer 1

Answer:

0.18

Step-by-step explanation:

The individual probabilities of each person eating the next fry must sum to 111. We know this because exactly one of the five people must eat each fry.

Hint #22 / 3

\begin{aligned}\text{P(M})+\text{P(R})+\text{P(L})+\text{P(A})+\text{P(C})&=1\\\\ 0.3+\text{P(R)}+0.1+0.32+0.1 &= 1 \\\\ \text{P(R)} &= 1-0.3-0.1-0.32-0.1 \\\\ \text{P(R)} & = \blueD{0.18} \end{aligned}  

P(M)+P(R)+P(L)+P(A)+P(C)

0.3+P(R)+0.1+0.32+0.1

P(R)

P(R)

​  

 

=1

=1

=1−0.3−0.1−0.32−0.1

=0.18

​  

 

Hint #33 / 3

The probability that Ronald will eat the next fry is \blueD{0.18}0.18start color #11accd, 0, point, 18, end color #11accd.

Answer 2

Answer:

0.18

Step-by-step explanation:

The individual probabilities of each person eating the next fry must sum to 111. We know this because exactly one of the five people must eat each fry.

\begin{aligned}\text{P(M})+\text{P(R})+\text{P(L})+\text{P(A})+\text{P(C})&=1\\\\ 0.3+\text{P(R)}+0.1+0.32+0.1 &= 1 \\\\ \text{P(R)} &= 1-0.3-0.1-0.32-0.1 \\\\ \text{P(R)} & = \blueD{0.18} \end{aligned}  

P(M)+P(R)+P(L)+P(A)+P(C)

0.3+P(R)+0.1+0.32+0.1

P(R)

P(R)

​  

 

=1

=1

=1−0.3−0.1−0.32−0.1

=0.18

​  

 

The probability that Ronald will eat the next fry is \blueD{0.18}0.18start color #11accd, 0, point, 18, end color #11accd.