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erma4kov [3.2K]
4 years ago
10

Cynthia is in the process of constructing two tangent line segments from a point outside circle O to circle O as shown. Which li

ne segments could she draw that would both be tangent to circle O?
A) segments MA and MB
B) segments MB and PB
C) segments PA and MA
D) segments PA and PB

Mathematics
2 answers:
Allisa [31]4 years ago
8 0

Answer:

(B) Segments MA and MB

Step-by-step explanation:

The tangent to the circle at a point is perpendicular to the radius of the circle drawn to the point of tangency.

Tangent at a point is unique.

Since there can be no two tangents at a point on circle, the options (b) and (c) are ruled out.

Now, if OA is perpendicular to MA, MA is the tangent else if OA is perpendicular to PA, PA is the tangent. Same is the case with point B.

Tangents from the same external point has same length.

MA = MB since they are the radii of the same circle with center M.

Hence, MA and MB meet all the requirements of the tangents.


Sphinxa [80]4 years ago
8 0

Answer:

D) segments PA and PB

Step-by-step explanation:

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To find ordered pair solutions, you could create an x and y graph and fill out the x side. Then, plug in an x number to get your y number and graph the ordered pairs to see if they give you a straight line. I'm going to use these numbers: -1, 0, 1, and 2.

...x...|...y...

\left[\begin{array}{ccc}-1&?\\0&?\\1&?\\2&?\end{array}\right]

Now, let's plug in -1 into the equation first to see what we get for y.

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Step 2:

With all that done, we can now fill out our table and graph the points.

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Here is the graph for the table above. I hope I helped you!

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