Find the area of each shape and add.Let's start with the first semi-circle(half-circle)
If the area of a circle is πr² , then the area of a semi-circle is 1/2πr² where is 22/7 or 3.14, and r is the radius which is 1.8 meters
A=1/2πr²
A=1/2*22/7*1.8*1.8
A=5.09 m²(rounded to nearest hundredth)
Since the semi-circles are two and have the same radius, multiply the area of the first one by two or go through the same process again.
So 5.09 *2=10.18meters square is the area of the two semi-circles
Now, let's find the area of a rectangle which is length times width, where length is 6 meters and width is (1.8+1.8, because 1.8 is half the width)=3.6 meters
A=l*w
A=6*3.6
A=21.6meters square
Therefore the area of the shape is 10.18m²+21.6m²=219.888m²
Answer:
function is a special type of relation where every input has a unique output
Step-by-step explanation:
Answer:
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Step-by-step explanation:
I had a test and this is the answer. :)
Answer:
Draw a straight line through these two points (0, 0) and (1, 3).
Step-by-step explanation:
"Proportional relationship" implies line or curve that goes through the origin; there is no "y-intercept" in this case.
Plot a dot at (0, 0). Next, move your pencil point 1 unit to the right (you'll end up at (1, 0), and then move it from there up to (1, 3). Draw a straight line through these two points (0, 0) and (1, 3).
First, find the slope of the line thru these 2 pts:
5-4
m = --------- = -1/2
2 -4
Use the slope-intercept formula y = mx + b:
5 = (-1/2)(2) + b. Then the y-intercept is 5 + 1, or 6: y = (-1/2)x + 6
Multiplying this entire result (3 terms) by 2 results in 2y = -x + 12, or
x + 2y = 12 (answer)