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romanna [79]
3 years ago
9

Find the slope of each line​

Mathematics
1 answer:
ki77a [65]3 years ago
5 0
-4 to +4. Is the answer
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1. You and your friend are going to Boston but
Nataly [62]

Answer:

speed acquired by me = 40 miles / hour

speed acquired by my friend = 50 miles / hour

Step-by-step explanation:

Here's the solution :-

time taken by both = 6 hours

( 10 AM - 4 PM )

1. Now, the required speed for me to reach boston at 4 PM is :

=》

\frac{distance}{time}

=》

\frac{240}{6}

=》

40 \: mph

2. Now, the required speed for my friend to reach boston at 4 PM is :

=》

\frac{distance}{time}

=》

\frac{300}{6}

=》

50 \: mph

3 0
2 years ago
Is the relationship between variables additives or multiplicative
mart [117]
Where is the question/example?
7 0
3 years ago
Read 2 more answers
Label the endpoints to round 21.897 to the nearest hundredth​
IrinaVladis [17]

Answer:

21.897 to the nearest hundredth is 2.19

3 0
2 years ago
What is the missing addend?<br> 52,835 +<br> = 87,216
posledela

Answer: 34,381

Step-by-step explanation:

You have to subtract 52,835 by the sum 87,216 which will get you the answer of 34,381

6 0
3 years ago
Read 2 more answers
Which of the following functions are solutions of the differential equation y'' + y = 3 sin x? (select all that apply)
DiKsa [7]

Answer:

C

Step-by-step explanation:

We must compute the derivatives and check if the equation is satisfied.

A. y'=(3\sin x)'=3\cos x. Differentiate again to get y''=(3\cos x)'=-3\sin x, then y''+y=-3\sin x+3\sin x=0\neq 3\sin x so this choice of y doesn't solve the equation.

B. y'=3\sin x+3x\cos x-5\cosx +5x\sin x=(5x+3)\sin x+(3x-5)\cos x and y''=5\sin x+(5x+3)\cos x+3\cos x-(3x-5)\sin x=(10-3x)\sin x+(5x+6)\cos x, then y''+y=10\sin x+6\cos x\neq 3\sin x so y is not a solution

C. y'=\frac{-3}{2}\cos x+\frac{3}{2}x\sin x hence y''=\frac{3}{2}\sin x+\frac{3}{2}\sin x+\frac{3}{2}x\cos x=3\sin x+\frac{3}{2}x\cos x. Then y''+y=3\sin x+\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\sin x so y is a solution.

D.y'=-3\sin x and y''=-3\cos x, then y''+y=0 thus y isn't a solution

E. y'=\frac{3}{2}\sin x+\frac{3}{2}x\cos x hence y''=\frac{3}{2}\cos x+\frac{3}{2}\cos x-\frac{3}{2}x\sin x=3\cos x-\frac{3}{2}x\cos x. Then y''+y=3\cos x-\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\cos x\neq 3\sin x then y is not a solution.

3 0
3 years ago
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