Question

Any one that knows this please help thanks!

Answer 1

Hereeeeeeeeeeeeeeeeeeeeee

Answer 2

$\frac{x^2-4}{x-8}$ to x = 4

$\frac{4^2-4}{4-8}$

$\frac{16-4}{-4}$

$-\frac{12}{4}$

$-3$