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2 years ago

Y=5/2x -4 how to graph it

1 answer:

8 0

Looking at y=-%285%2F2%29x we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=-5%2F2 and the y-intercept is b=0 note: y=-%285%2F2%29x really looks like y=-%285%2F2%29x%2B0

Since b=0 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point

Now since the slope is comprised of the "rise" over the "run" this means

slope=rise%2Frun

Also, because the slope is -5%2F2, this means:

rise%2Frun=-5%2F2

which shows us that the rise is -5 and the run is 2. This means that to go from point to point, we can go down 5 and over 2

So starting at , go down 5 units

and to the right 2 units to get to the next point

Now draw a line through these points to graph y=-%285%2F2%29x

So this is the graph of y=-%285%2F2%29x through the points

Hope this helps

Please give me Brainliest

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Richard cuts a piece of wood for a project. The first cut is shown and can be represented by the equation y = 1/2x + 2. The Seco

Morgarella [4.7K]

Since it is parallel, gradient must be the same so it will be 1/2
y=1/2x+c
-7=1/2(0)+c
c=-7
equation is y=1/2x-7

5 0

3 years ago

Read 2 more answers

Estimate the area of Alberta in square miles. Show your reasoning

ella [17]

Answer: About $278,250\ mi^2$

Step-by-step explanation:

The missing figure is attached.

Notice in the first picture that Alberta has a complex shape.

You can calculate the area of a complex shape by decomposing it into polygons whose areas can be calculated easily.

Observe the second picture. Notice that it can be descompose into two polygons: A trapezoid and a rectangle.

The area of the trapezoid can be calcualted with the formula:

$A_t=\frac{h}{2}(B+b)$

Where "h" is the height, "B" is the long base and "b" is short base.

And the area of the rectangle can be found with the formula:

$A_r=lw$

Wkere "l" is the lenght and "w" is the width.

Then, the apprximate area of Alberta is:

$A=\frac{h}{2}(B+b)+lw$

Substituting vallues, you get:

$A=(\frac{(410\ mi-180\ mi)}{2})(760\ mi+470\ mi)+(180\ mi)(760\ im)\\\\A=141,450\ mi^2+136,800\ mi^2\\\\A=278,250\ mi^2$

Therefore, the area of of Alberta is about $278,250\ mi^2$ .

5 0

2 years ago

1.01<0.99 true,4.5=4.50 true, 3.5<3.39 true?, lastly is 1.51>1.15 true?

kirza4 [7]

No, yes, no, yes

What part of comparing number values do you not understand? Most folks figure out enough about place value to be able to answer this by 3rd grade. If there's something about this question that really stumps you, please advise in the comments.

5 0

2 years ago

HELP PLZ!

Elza [17]

Answer:

$-5 = y$