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Scorpion4ik [409]
3 years ago
12

Y=5/2x -4 how to graph it

Mathematics
1 answer:
Igoryamba3 years ago
8 0

Looking at y=-%285%2F2%29x we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=-5%2F2 and the y-intercept is b=0 note: y=-%285%2F2%29x really looks like y=-%285%2F2%29x%2B0

Since b=0 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point  

Now since the slope is comprised of the "rise" over the "run" this means

slope=rise%2Frun

Also, because the slope is -5%2F2, this means:

rise%2Frun=-5%2F2

which shows us that the rise is -5 and the run is 2. This means that to go from point to point, we can go down 5 and over 2

So starting at , go down 5 units

and to the right 2 units to get to the next point  

Now draw a line through these points to graph y=-%285%2F2%29x

So this is the graph of y=-%285%2F2%29x through the points  

Hope this helps

Please give me Brainliest

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A marketing researcher wants to find a 96% confidence interval for the mean amount those visitors spend per person per day while
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Answer:

n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38

So then the minimum sample to ensure the condition given is n= 38

Step-by-step explanation:

Notation

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

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n represent the sample size  

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Solution to the problem

When we create a confidence interval for the mean the margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =4 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 96% of confidence interval now can be founded using the normal distribution. The significance is \alpha=1-0.96 =0.04. And in excel we can use this formula to find it:"=-NORM.INV(0.02;0;1)", and we got z_{\alpha/2}=2.054, replacing into formula (b) we got:

n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38

So then the minimum sample to ensure the condition given is n= 38

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