Since it is parallel, gradient must be the same so it will be 1/2
y=1/2x+c
-7=1/2(0)+c
c=-7
equation is y=1/2x-7
Answer: About
Step-by-step explanation:
The missing figure is attached.
Notice in the first picture that Alberta has a complex shape.
You can calculate the area of a complex shape by decomposing it into polygons whose areas can be calculated easily.
Observe the second picture. Notice that it can be descompose into two polygons: A trapezoid and a rectangle.
The area of the trapezoid can be calcualted with the formula:

Where "h" is the height, "B" is the long base and "b" is short base.
And the area of the rectangle can be found with the formula:

Wkere "l" is the lenght and "w" is the width.
Then, the apprximate area of Alberta is:

Substituting vallues, you get:

Therefore, the area of of Alberta is about
.
No, yes, no, yes
What part of comparing number values do you not understand? Most folks figure out enough about place value to be able to answer this by 3rd grade. If there's something about this question that really stumps you, please advise in the comments.
Answer:

Step-by-step explanation:
{y = 6x − 11
{y = x² + 4x − 10
x² + 4x − 10 = 6x − 11
- [6x − 11] - [6x − 11]
________________________
x² - 2x + 1
![{[x - 1]}^{2} = 0](https://tex.z-dn.net/?f=%7B%5Bx%20-%201%5D%7D%5E%7B2%7D%20%3D%200)
1 = x [Plug this back into both equations above to get the y-coordinate of −5]; −5 = y
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