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DiKsa [7]
3 years ago
9

How many possible combinations comes from a word with five letters?

Mathematics
1 answer:
ANEK [815]3 years ago
8 0
There's over 400,000 combinations
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Pls help. i don't like math
ANTONII [103]

Answer:

X = 5 3/8 (5 and 3 eighths)

Step-by-step explanation:

4/5x = 5 1/5 - 9/10

4/5x = 43/10

x=43/8

x= 5 3/8

4 0
3 years ago
Read 2 more answers
2x + 4 = 4x how. to solve it ​
ipn [44]

Answer:

x=2

Step-by-step explanation:

2x+4=4x

-2x     -2x  

4=2x/2x

4/2=x

x=2

8 0
3 years ago
Read 2 more answers
The Wall Street Journal reported that the age at first startup for 90% of entrepreneurs was 29 years of age or less and the age
Hitman42 [59]

Answer:

(a) \hat p\sim N(0.90,\ 0.0212^{2}})

(b) \hat q\sim N(0.10,\ 0.0212^{2}})

(c) Not different.

Step-by-step explanation:

The information provided is:

  • The age at first startup for 90% of entrepreneurs was 29 years of age or less.
  • The age at first startup for 10% of entrepreneurs was 30 years of age or more.

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

 \sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

(a)

Let <em>p</em> represent the proportion of entrepreneurs whose first startup was at 29 years of age or less.

A sample of <em>n</em> = 200 entrepreneurs is selected.

As <em>n</em> = 200 > 30, according to the Central limit theorem the sampling distribution of sample proportion can be approximated by the normal distribution.

Compute the mean and standard deviation as follows:

\mu_{\hat p}=p=0.90\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.90(1-0.90)}{200}}=0.0212

So, \hat p\sim N(0.90,\ 0.0212^{2}}).

(b)

Let <em>q</em> represent the proportion of entrepreneurs whose first startup was at 30 years of age or more.

A sample of <em>n</em> = 200 entrepreneurs is selected.

As <em>n</em> = 200 > 30, according to the Central limit theorem the sampling distribution of sample proportion can be approximated by the normal distribution.

Compute the mean and standard deviation as follows:

\mu_{\hat q}=q=0.10\\\\\sigma_{\hat q}=\sqrt{\frac{q(1-q)}{n}}=\sqrt{\frac{0.10(1-0.10)}{200}}=0.0212

So, \hat q\sim N(0.10,\ 0.0212^{2}}).

(c)

The standard deviation of sample proportions is also known as the standard error.

The standard deviation of <em>p</em> is, 0.0212.

The standard deviation of <em>q</em> is, 0.0212.

Thus, the standard errors of the sampling distributions in parts (a) and (b) are same.

5 0
3 years ago
Find an explicit rule for the nth term of the sequence.<br><br> -5, -25, -125, -625, ...
Angelina_Jolie [31]

Answer:

Work shown below!

Step-by-step explanation:

a_{n}=a*r^{n-1} \\a_{n}=-5*5^{n-1} \\

8 0
3 years ago
What the puzzle combination
Arte-miy333 [17]

Answer:

Step-by-step explanation:

2

2

2

1

Download pdf
7 0
4 years ago
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