What is the LCD of 3/5 and 1/6
1 answer:
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The probability that the transistor will last between 12 and 24 weeks is 0.424
X= lifetime of the transistor in weeks E(X)= 24 weeks
O,= 12 weeks
The anticipated value, variance, and distribution of the random variable X were all provided to us. Finding the parameters alpha and beta is necessary before we can discover the solutions to the difficulties.
X~gamma()
E(X)=
=
=6 weeks
V(x)=
=24/6= 4
Now we can find the solutions:
The excel formula used to create Figure one is as follows:
=gammadist(X, ,
, False)
P()
P()
P()
P= 0.424
Therefore, probability that the transistor will last between 12 and 24 weeks is 0.424
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