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mars1129 [50]
3 years ago
7

-/1 points

Mathematics
1 answer:
MatroZZZ [7]3 years ago
5 0
<h3>If the width w is 55 feet and the perimeter P is 290 feet. </h3><h3>Use the formula P = 21 + 2w to find the length</h3>

<em><u>Solution:</u></em>

<em><u>The perimeter of rectangle is given as:</u></em>

P = 2(length + width)

From given,

length = ?

width = 55 feet

perimeter = 290 feet

Therefore,

290 = 2(length + 55)

length + 55 = \frac{290}{2}\\\\length + 55 = 145\\\\length = 145 - 55\\\\length = 90

Thus length of rectangular lot is 90 feet

<h3>Use the equation y = (x + 1)2 - 10 to find the value of y when x is -2</h3>

<em><u>Solution:</u></em>

<em><u>Given equation is:</u></em>

y = (x + 1)^2 - 10

To find: y when x = -2

Substitute x = -2

y = (-2 + 1)^2 -10\\\\y = -1^2 -10\\\\y = 1 - 10\\\\y = -9

Thus y is -9 when x is -2

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