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<h3>If the width w is 55 feet and the perimeter P is 290 feet. </h3><h3>Use the formula P = 21 + 2w to find the length</h3>

<em><u>Solution:</u></em>

<em><u>The perimeter of rectangle is given as:</u></em>

P = 2(length + width)

From given,

length = ?

width = 55 feet

perimeter = 290 feet

Therefore,

290 = 2(length + 55)

$length + 55 = \frac{290}{2}\\\\length + 55 = 145\\\\length = 145 - 55\\\\length = 90$

Thus length of rectangular lot is 90 feet

<h3>Use the equation y = (x + 1)2 - 10 to find the value of y when x is -2</h3>

<em><u>Solution:</u></em>

<em><u>Given equation is:</u></em>

$y = (x + 1)^2 - 10$

To find: y when x = -2

Substitute x = -2

$y = (-2 + 1)^2 -10\\\\y = -1^2 -10\\\\y = 1 - 10\\\\y = -9$

Thus y is -9 when x is -2

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How do you graph a circle x^2 + y^2=25 and the line is given y=2

Kazeer [188]

$\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}
\end{array}\\\\
-------------------------------\\\\
x^2+y^2=25\implies (x-0)^2+(y-0)^2=5^2$

so notice above, the circle is centered at h,k or 0,0, the origin, and has a ratio of 5.

and y = 2, is just a horizontal line, check the picture below.