7 less than one fourth of x is y

Sebastian leaves £3000 in the bank for two years.

nevsk [136]

40000 is the answer man shdjdorjnekdbebrjf

6 0

3 years ago

The graph of y = 4 – is shown.

Ratling [72]

Rather than try to select the correct answer without doing work, I'd rather do the work first and the matching later.

Given y = 4 - x, or y = 4 - 1x,

1) the y-intercept is (0,4).
2) this being a linear function, it has neither maximum nor minimum.
3) the x-intercept is found by letting y = 0 and solving for x: 0 = 4 - x; x - 4. The x-intercept is (4,0).

Which of the given statements is true?

7 0

3 years ago

A trapezoid has 8.2 millimeters base and 5.2 millimeters base, as well as 10 millimeters height. What is the area?

Savatey [412]

Answer:

67 mm

Step-by-step explanation:

use area of a trap formula:

b1+b2 /2*h

b1=base

b2=base

h=height

in our case it was, 8.2+5.2/2*10

67

6 0

3 years ago

X and y are normal random variables with e(x) = 2, v(x) = 5, e(y) = 6, v(y) = 8 and cov(x,y)=2. determine the following: e(3x 2y

andriy [413]

The result for the given normal random variables are as follows;

a. E(3X + 2Y) = 18

b. V(3X + 2Y) = 77

c. P(3X + 2Y < 18) = 0.5

d. P(3X + 2Y < 28) = 0.8729

<h3>What is normal random variables?</h3>

Any normally distributed random variable having mean = 0 and standard deviation = 1 is referred to as a standard normal random variable. The letter Z will always be used to represent it.

Now, according to the question;

The given normal random variables are;

E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8.

Part a.

Consider E(3X + 2Y)

$\begin{aligned}E(3 X+2 Y) &=3 E(X)+2 E(Y) \\&=(3) (2)+(2)(6 )\\&=18\end{aligned}$

Part b.

Consider V(3X + 2Y)

$\begin{aligned}V(3 X+2 Y) &=3^{2} V(X)+2^{2} V(Y) \\&=(9)(5)+(4)(8) \\&=77\end{aligned}$

Part c.

Consider P(3X + 2Y < 18)

A normal random variable is also linear combination of two independent normal random variables.

$3 X+2 Y \sim N(18,77)$

Thus,

$P(3 X+2 Y < 18)=0.5$

Part d.

Consider P(3X + 2Y < 28)

$Z=\frac{(3 X+2 Y-18)}{\sqrt{77}}$

$\begin{aligned} P(3X + 2Y < 28)&=P\left(\frac{3 X+2 Y-18}{\sqrt{77}} < \frac{28-18}{\sqrt{77}}\right) \\&=P(Z < 1.14) \\&=0.8729\end{aligned}$

Therefore, the values for the given normal random variables are found.

To know more about the normal random variables, here

brainly.com/question/23836881

#SPJ4

The correct question is-

X and Y are independent, normal random variables with E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8. Determine the following:

a. E(3X + 2Y)

b. V(3X + 2Y)

c. P(3X + 2Y < 18)

d. P(3X + 2Y < 28)

8 0

2 years ago

Values of k for which the quadratic equation 2x - kx + k 0 has equal roots is

WARRIOR [948]

Answer:

The answer is D.

Step-by-step explanation:

We have to apply Discriminant Law. When a quadratic equation, ax² + bx + c = 0 has equal roots so the discriminant will be 0. Then, you have to substitute the values into the formula :

$D = {b}^{2} - 4ac$

$let \: D = 0 ,a = 2,b = k,c = k$

$0 = {k}^{2} - 4(2)(k)$

${k}^{2} - 8k = 0$

$k(k - 8) = 0$

$k = 0$

$k - 8 = 0$

$k = 8$

4 0

3 years ago