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enyata [817]
3 years ago
9

2x+y=8 What is the work for it?

Mathematics
1 answer:
weqwewe [10]3 years ago
4 0

Answer:

y= -2x+8

Step-by-step explanation:

2x+y=8

-2x     -2x

__________

y= -2x+8

I think this is what you're asking for. The question is kind of confusing.

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MUSIC Thirty-six percent of the songs on your MP3 player are pop songs.
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Answer:

.36

Step-by-step explanation:

36% -> 36/100 -> .36

3 0
3 years ago
What are the values for the coefficients and constant term of 0 = 2 + 3x2 – 5x?
Mekhanik [1.2K]

This is a quadratic in the form of ax squared +bx +c

So

a = 3

b = -5

c = 2

Hope this helps!

3 0
3 years ago
Read 2 more answers
Which function passes through the points (2, 3) and (4, 4)?
Anon25 [30]

Answer: c

Step-by-step explanation:

3 0
3 years ago
I need help on numbers 11-16
agasfer [191]
Recall your SOH CAH TOA, or \bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}

now, bear in mind that, the opposite side, to an angle, is the side right "in front of it", that is, if you were to put your eye on that angle, "the wall" you'd see on the other end, is the opposite side

the adjacent side, adjacent = next to, is the side that's touching the angle itself

and the hypotenuse, is always the slanted and longest side of all three

for example on 16, tangent of Z

if you put one eye on Z, you'll see on the other end, the side of 30 units
the adjacent side is the one touching Z, or the 40 units side

\bf tan(\theta)=\cfrac{opposite}{adjacent}\implies tan(Z)=\cfrac{30}{40}
\\\\\\
\textit{which can be simplified to }\cfrac{3}{4}


and you'd do all others, the same way, using those ratios

use \bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
8 0
3 years ago
Complete the table using the equation Y=3x+2
Brut [27]
Where is the table i dont see it 
7 0
4 years ago
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