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Dmitry_Shevchenko [17]
3 years ago
13

The polygons below are similar. Set up a proportion

Mathematics
1 answer:
m_a_m_a [10]3 years ago
4 0

Answer:

<em>x = 42 </em>

Step-by-step explanation:

\frac{18}{15} = \frac{x}{35} ⇔ \frac{6}{5} = \frac{x}{35} ⇔ \frac{6*7}{5*7} = \frac{x}{35} ⇒ <em>x = 42</em>

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Work out 1% of 200 litres<br> need explination
Varvara68 [4.7K]

ANSWER

2

To find 1% of something (1/100 of something), divide by 100.

1% of 200 is 2.

6 0
3 years ago
2. If 15 tickets for a baseball game cost $97.<br> how many tickets can be bought for $71.)
attashe74 [19]

Answer:

technically only 10 but if you round up then its 11.

Step-by-step explanation:

97 divided by 15 ~6.47

71 divided by 6.47~ 10.97

6 0
4 years ago
Someone help. pls and ty answer only if u know the answer pls
zmey [24]

Answer:

It is not permitted the denominator to be zero as we can't divide by zero.

<u>Non- permissible values are:</u>

a)  

  • ab² = 0
  • a = 0, b = 0

b)  

  • 3n + 1 = 0
  • n = -1/3

c)  

  • 4 - a = 0
  • a = 4

d)  

  • x² - x - 12 = 0  
  • (x - 4)(x + 3) = 0
  • x = 4 or x = -3

e)  

  • 10x³ - 92x² + 18x = 0
  • 2x(5x² - 46x + 9) = 0
  • x(5x - 1)(x - 9) = 0
  • x = 0, x = 1/5, x = 9
4 0
3 years ago
Pls answer! I don’t know math @ all
Lana71 [14]

The probability that the outcome is a sum that is a multiple of 6 or a sum that is a multiple of 4 is \frac{5}{12}.

Solution:

Total number of outcomes N(S) = 36

Let A be the sum that is a multiple of 6 and

B be the sum that is a multiple of 4.

Sum that is a multiple of 6 = (1, 5), (2, 4), (3, 3), (4, 2), (5, 1), (6, 6)

N(A) = 6

Sum that is a multiple of 4 = (1, 3), (2, 2), (2, 6), (3, 1), (3, 5),

                                              (4, 4), (5, 3), (6, 2), (6, 6)

N(B) = 9

$P(A)=\frac{N(A)}{N(S)}

$P(A)=\frac{6}{36}=\frac{1}{6}

$P(B)=\frac{N(B)}{N(S)}

$P(B)=\frac{9}{36}=\frac{1}{4}

Probability that the outcome is a sum that is a multiple of 6 or a sum that is a multiple of 4:

P(A \cup B)=P(A)+P(B)

$P(A \cup B)=\frac{1}{6} +\frac{1}{4}

               $=\frac{2+3}{12} (Make the denominator same)

               $=\frac{5}{12}

Hence the probability that the outcome is a sum that is a multiple of 6 or a sum that is a multiple of 4 is \frac{5}{12}.

8 0
3 years ago
F(x) = x2 + 1<br> What is f(f(x))?<br> O A+ 2x2+1<br> A+ 2x2+2<br> O A +2<br> O A+1
Gennadij [26K]

Answer:

Your answer is x^4 + 2 x^2 +2

Hope that this is helpful. Vote and like it

6 0
3 years ago
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