It shows the Ora scale for area multiply width and length
Answer:
Simple interest = PRT/100
300 = 150 x 4 x T/100
2 x 100/4 = T
Therefore T = 50 years
Hope this helps!
Mean of the distribution = u = 222
Standard Deviation = s = 16
We have to find the probability that a value lies between 190 and 230.
First we need to convert these data values to z score.

For x = 190,

For x = 230

So, we have to find the percentage of values lying between z score of -2 and 0.5
P( -2 < z < 0.5) = P(0.5) - P(-2)
From standard z table, we can find and use these values.
P(-2 < x < 0.5 ) = 0.6915 - 0.0228 = 0.6687
Thus, there is 0.6887 probability that the data value will lie between 190 and 230 for the given distribution.
Answer:
p^(-9) or 1/p^9
Step-by-step explanation:
Here we have:
(5p)^(-7)
----------------
(20p)^2
Let's temporarily remove the coefficient 5/20 and reduce it to 1/4.
then we have:
1 1 1
(1/4) ------------- = (1/4) -------------- = ------------
p^7*p^2 p^(7 + 2) p^9
Answer: Don't know sorry
Step-by-step explanation: