The diagonals of rhombus WXYZ intersect at point P. If WP = 12 and XP = 5, find the perimeter of the rhombus.
2 answers:
Answer with explanation:
WP=12 units
XP=5 units
Diagonals of rhombus bisect each other at right angles.as well as All sides of Rhombus are equal.
∠WPX=∠XPY=∠ZPY=∠WPZ=90°
Using Pythagoras theorem In Δ WPX
WX²=WP²+PX²
=12²+5²
WX²=144+25
WX²=169
WX=√169
WX=13 units
Perimeter of Rhombus WXYZ=4 × Side length (WX)
=4 × 13
= 52 Units
Answer: 52 Use the pythagorean theorum to calculate WX, since it's a rhombus, all sides are equal, multiply by four, finished.
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Well, if it is increasing at a fixed rate of 2 mm/s, then the volume would still be increasing at a rate of 2 mm/s when the diameter is 80 mm, if I understand your question correctly.
a= -66
-11=a/6
-66=a
a=-66
hopes this helps,
Xeno
3, 217 Sorry if it’s wrong Hope this helped *smiles*
(9y+y) + (6+3) The answer is 10y+9