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3 years ago

13

Which shows all the names that apply to the figure?

2 answers:

podryga [215]3 years ago

8 0

B. This is classified as a parallelogram and a rhombus.

Lorico [155]3 years ago

5 0

<span>B. parallelogram, rhombus</span>

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Theater m has 25 rows with 27 seats in each row. how many of the seats were occupiedduring a certain show?(1) during the show, t

Elis [28]

1) 475
2)375
You need to multiply 25 by 27 and you get 675 then to get answer one you need to multiply 10 by 20 to get 200 the take 200 away from 675 to get 475 then do the same thing with the second problem 20x15 which is 300 the take 300 away from 675.

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3 years ago

Is my answer correct? If not please help.

DerKrebs [107]

I think you are correct

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2 years ago

Can someone help me please!

Alex777 [14]

Answer:

4x^2+17x+15

Step-by-step explanation:

(4x-3)(x+5)

= 4x(x+5) -3(x+5)

= 4x^2+ 20x -3x + 15

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3 years ago

Order the fractions below from least to greatest.<br> 1/2, 2/3, 1/4, 5/6

Natali [406]

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3 years ago

Read 2 more answers

Three people pull simultaneously on a stubborn donkey. Jack pulls directly ahead of the donkey with a force of 90.5 N , Jill pul

Radda [10]

Answer:

Fn= 174.9 N : Magnitude of the net force the people exert on the donkey.

Step-by-step explanation:

We find the components of the forces in x-y-z

Force of Jack in z =F₁z=90.5 N in direction (+z)

Force of Jill in x = F₂x= -82.3*cos45°= - 58.19 N (-x)

Force of Jill in y =F₂y=-82.3*sin45°= + 58.19 N (+y)

Force of Jane in x =F₃x=125*cos45°= + 88.4 N (+x)

Force of Jane in y =F₃y=125*sin45°= + 88.4 N (+y)

Calculating of the components of the net force the people exert on the donkey.

Fnx= F₂x+F₃x=( - 58.19+ 88.4 )N=30.2N (+x)

Fny= F₂y+F₃y=( 58.19+88.4 ) = 146.59 N (+y)

Fnz =F₁z=90.5 N (+z)

Calculating of the magnitude of the net force the people exert on the donkey.

$F_{n} =\sqrt{(F_{nx})^{2}+(F_{ny}) ^{2} +(F_{nz}) ^{2} }$

$F_{n} =\sqrt{(30.2)^{2}+( 146.59) ^{2} +(90.5) ^{2} }$

$F_{n} = 174.9 N$

7 0

3 years ago