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2 years ago

10

A lawn service charges 28 dollars per lawn. If the lawn service earns 252 dollars in a day, write an equation to represent the n

umber of lawns the company serviced.

2 answers:

kow [346]2 years ago

5 0

252 divided by 28= 9
So they mowed 9 lawns in one day.

miv72 [106K]2 years ago

4 0

$252/$28=9 lawns. $252 is the total money they earned, so divide it by the amount of money they charge per lawn.

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There are 15 girls and 12 boys in Ms. Grady's 6th period class. Ms. Grady

ziro4ka [17]

Answer:

5/9

Step-by-step explanation:

Step 1:

15 + 12

Step 2:

27

Step 3:

15/27

Step 4:

15/27 = 5/9

Answer:

5/9

Hope This Helps :)

5 0

2 years ago

A friend calls you and asks you to meet at the park 2 mi away in 25 min. You set off on your skateboard after the call. At what

xeze [42]

Answer:

speed greater than 0.08 mi/min

Step-by-step explanation:

given data

distance = 2 mi

time = 25 min

to find out

the distance you travel and your speed and time related

solution

we know that distance is

distance = speed × time ...............1

so at park at most 25 min

so we need time = $\frac{distanec}{speed} \leq 25$

so here

we know

$\frac{2}{25} \leq speed$

so

$0.08 \leq speed$

so we can say that he need to run at speed greater than 0.08 mi/min

8 0

2 years ago

A football is kicked toward an end zone with an initial vertical velocity of 30 ft/s. The function h(t) = -16+ 30t models the he

Ulleksa [173]

Answer:

A. The football does not reach a height of 15ft

Step-by-step explanation:

Given

$h(t) = -16t^2 + 30t$

Required

Determine which of the options is true

The option illustrates the height reached by the ball.

To solve this, we make use of maximum of a function

For a function f(x)

Such that:

$f(x) = ax^2 + bx + c$ :

$f(\frac{-b}{2a}) = maximum/minimum$

i.e we first solve for $\frac{-b}{2a}$

Then substitute $\frac{-b}{2a}$ for x in $f(x) = ax^2 + bx + c$

In our case:

First we need to solve $\frac{-b}{2a}$

Then substitute $\frac{-b}{2a}$ for t in $h(t) = -16t^2 + 30t$

By comparison:

$b = 30$

$c = -16$

$\frac{-b}{2a} = \frac{-30}{2 * -16}$

$\frac{-b}{2a} = \frac{-30}{-32}$

$\frac{-b}{2a} = \frac{30}{32}$

$\frac{-b}{2a} = \frac{15}{16}$

Substitute $\frac{15}{16}$ for t in $h(t) = -16t^2 + 30t$

$h(\frac{15}{16}) = -16(\frac{15}{16})^2 + 30(\frac{15}{16})$

$h(\frac{15}{16}) = -16(\frac{225}{256}) + \frac{450}{16}$

$h(\frac{15}{16}) = -(\frac{225}{16}) + \frac{450}{16}$

$h(\frac{15}{16}) = \frac{-225 + 450}{16}$

$h(\frac{15}{16}) = \frac{225}{16}$

$h(\frac{15}{16}) = 14.0625$

This implies that the maximum height reached is 14.0625ft.

So, the option that answers the question is A because $14.0625 < 15$

8 0

2 years ago

On April 11, 2012, two earthquakes were measured off the northwest coast of Sumatra. The first had a magnitude of 8.6. The secon

Hoochie [10]

Answer:

Option D. 2.51 is correct.

Step-by-step explanation:

Magnitude of first earthquake = 8.6

Let intensity of first earthquake be x

$Magnitude = \log(\frac{x}{S}),\text{ where S is seismographic factor}\\\\\implies 8.6=\log(\frac{x}{S}).......(1)$

Magnitude of second earthquake = 8.2

Let intensity of second earthquake be y

$Magnitude = \log(\frac{y}{S}),\text{ where S is seismographic factor}\\\\\implies 8.2=\log(\frac{y}{S}).......(2)$

Now, to find the factor by which intensity of first earthquake is greater than intensity of second : we divide equation (1) by equation (2)

$\implies\log(\frac{x}{y})=8.6 - 8.2\\\\\implies \log(\frac{x}{y})=0.4\\\\\implies\frac{x}{y}=10^{0.4}\\\\\implies\frac{x}{y}=2.51$

Hence the required factor is 2.51

Therefore, Option D. 2.51 is correct.

4 0

2 years ago

Ken spent 1/5 of his allowance on a movie, 3/8 on snacks, and 2/7 on games. If his allowance was $20, how much did Ken have left

Wewaii [24]

1/5 of 20 is $4. So, 20-4=$16 remaining.
3/8 of 16 is $7.50. So, 16-7.50= $8.50 remaining.
2/7 of 8.5 is $2.43. So, 8.50-2.43 is $6.07

Answer: Ken has $6.07 left after all his purchases.

6 0

3 years ago

Read 2 more answers