A student has received 56, 70, 61 and 46 on his first four college algebra exams this semester. He asked the instructor what gra
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The correct answer would be 3 +/- 
In order to solve for this you must first get the equation equal to 0.
x^2 + 6x + 9 - 6 ----> simplify like terms
x^2 + 6x + 3
Now knowing this we can use the coefficients of each one in descending order of power as a, b and c.
a = 1 (because it is the coefficient to x^2)
b = 6 (because it is the coefficient to x)
c = 3 (because it is the end number)
Now we can plug these values into the quadratic equation.
3 +/-
And those would be your two answers.
In order to solve for this you must first get the equation equal to 0.
x^2 + 6x + 9 - 6 ----> simplify like terms
x^2 + 6x + 3
Now knowing this we can use the coefficients of each one in descending order of power as a, b and c.
a = 1 (because it is the coefficient to x^2)
b = 6 (because it is the coefficient to x)
c = 3 (because it is the end number)
Now we can plug these values into the quadratic equation.
3 +/-
And those would be your two answers.