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SSSSS [86.1K]
3 years ago
9

A student has received 56, 70, 61 and 46 on his first four college algebra exams this semester. He asked the instructor what gra

de he would need to make on the fifth exam to pass the course. What score will he need to earn to receive 70% or higher on the fifth exam? Set up an equation/inequality and show all work and find the solution.
Please help!
Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
7 0

Let x be the mark he would attain at the fifth exam. Then,

\frac{56+70+61+46+x}{5} \geq 70

\frac{273+x}{5} \geq 70

273 + x ≥ 350

x ≥ 350 - 273

x ≥ 77

So, he should score 77 or more marks in his fifth exam.

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1 year ago
What is a number increased by 7 multiplied by 4?
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9?

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4 0
3 years ago
Solve for x9(x + 1) = 25 + x
vaieri [72.5K]
When you expand the equation, you will have
9x + 9=25 + x
Next you have to collect like terms
+x will go over the equality sign to become -x. The same applies to +9
9x - x=23 - 9
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8x=14
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x=14/8
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8 0
3 years ago
Read 2 more answers
Convert 3 quarts to pints
ss7ja [257]

Answer:

6 pints

Step-by-step explanation:

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Hope this helps!

4 0
3 years ago
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Two dice are rolled; find the probability of rolling a doubles (2 of a kind) or getting two numbers whose sum is equal to 8.
emmainna [20.7K]

Answer:

The probability of rolling a doubles or getting two numbers whose sum is equal to 8 is 0.278.

Step-by-step explanation:

There are a total of <em>N</em> = 36 outcomes when rolling two fair dice.

The outcomes for rolling doubles are: {(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)}.

So, n (Doubles) = n (D) = 6

The outcomes for rolling a sum of 8 are: {(2, 6), (3, 5), (4, 4), (5, 3), (6, 2)}

So, n (Sum 8) = n (S8) = 5

Considering the outcomes of the above two events, it can be seen that there is a common outcome, i.e. (4, 4).

So, n (D ∩ S8) = 1

Compute the probability of rolling a doubles or getting two numbers whose sum is equal to 8 as follows:

P(D\cup S8)=P(D)+P(S8)-P(D\cap S8)

                 =\frac{n(D)}{N}+\frac{n(S8)}{N}-\frac{n(D\cap S8)}{N}\\\\=\frac{6}{36}+\frac{5}{36}-\frac{1}{36}\\\\=\frac{6+5-1}{36}\\\\=\frac{10}{36}\\\\=0.278

Thus, the probability of rolling a doubles or getting two numbers whose sum is equal to 8 is 0.278.

4 0
2 years ago
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