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aksik [14]
4 years ago
9

have The Shroud of Turin, which shows the negative image of the body of a man who appears to have been crucified, is believed by

many to be the burial shroud of Jesus of Nazareth. In 1988 the Vatican granted permission to have the shroud carbon-dated. Three independent scientific laboratories analyzed the cloth and concluded that the shroud was approximately 660 years old,t an age consistent with its historical appearance. Using this age, determine what percentage of the original amount of C-14 remained in the cloth as of 1988. (The half-life of C-14 is approximately 5730 years. Round your answer to the nearest percent.) in the clothn
Mathematics
1 answer:
Jlenok [28]4 years ago
5 0

Answer:94%

Step-by-step explanation:

Half life of a radioactive element is the time taken for half it's mass to disintegrate away.it means after attaining half life,what will be left is 100-50=50%.

Let the 100% mass of C-14,be x

Then 5730years=1/2 of X

Then 660 years=y of X

Where Y is the fraction of C-14 that has disintegrate as at 1988.

5730/660=1/2X/yX

5730/660=1/2/y

Cross multiplying

5730×y=660×1/2

5730y=330

Y=330/5730=0.05759

In %,5.76%

Amount of C-14 left is

100-5.76=94.24=94% as at 1988.

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GrogVix [38]

Elimination method:

4m = n + 7

3m + 4n + 9 = 0

<em>First, let's get the equations in the same form.</em>

4m - n - 7 = 0

3m + 4n + 9 = 0

<em>Now let's make multiply the first equation by 4 so we can eliminate n.</em>

16m - 4n - 28 = 0

+3m + 4n + 9 = 0

<em>Now we can add the equations.</em>

16m + 3m - 4n + 4n - 28 + 9 = 0

19m + 0n - 19 = 0

19m - 19 = 0

19m = 19

<em>m = 1</em>

<em>Now we put m back into one (or both) of the original equations.</em>

4(1) = n + 7

4 = n + 7

<em>n = -3</em>

<em>If you plug m into the other equation, you get the same result.</em>

<em />

Substitution method:

4m = n + 7

3m + 4n + 9 = 0

<em>With this method, we plug one of the equations into the other one. I'm going to use m in the second equation as a substitute for m in the second equation.</em>

3m + 4n + 9 = 0

3m = -4n - 9

m = (-4/3)n - 3

<em>Now I can substitute the right side into the first equation like so:</em>

4[(-4/3)n - 3] = n + 7

(-16n)/3 - 12 = n + 7

(-16n)/3 = n + 19

-16n = 3(n + 19)

-16n = 3n + 57

0 = 16n + 3n + 57

0 = 19n + 57

0 = 19n/19 + 57/19

0 = n + 3

<em>-3 = n</em>

<em>And then we put that back into one of the original equations.</em>

4m = n + 7

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Hopefully you learned something from this.

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3 years ago
Franchise Business Review stated over 50% of all food franchises earn a profit of less than $50,000 a year. In a sample of 130 c
nydimaria [60]

Answer:

We need a sample size of 564.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

\pi = \frac{81}{130} = 0.6231

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Based upon a 95% confidence interval with a desired margin of error of .04, determine a sample size for restaurants that earn less than $50,000 last year.

We need a sample size of n

n is found when M = 0.04

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.6231*0.3769}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.6231*0.3769}

\sqrt{n} = \frac{1.96\sqrt{0.6231*0.3769}}{0.04}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.6231*0.3769}}{0.04})^{2}

n = 563.8

Rounding up

We need a sample size of 564.

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