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Llana [10]
3 years ago
11

Please help!!!! I only need to do A not B!!! 8 points!!!!

Mathematics
1 answer:
Nadya [2.5K]3 years ago
8 0
2/5+-1/3 please excuse my sloppy writing

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Solve the equation for y.<br> 8x – 9y = 11
pav-90 [236]
8x-9y=11

First you move the 8x because you have to leave the 9y alone

8x-9y=11
-8x        -8x

-9y=11-8x

Now you have to move the -9, so the inverse of multiplying is dividing so you divide -9.

-9y/-9= 11/-9 -8x/-9

since you can't have negative as a denominator it would be:

y= -11/9+8x/9

<span>You have to change the signs</span>
3 0
3 years ago
Help ASAP i need a lot of help
sleet_krkn [62]

Answer:

12.

Step-by-step explanation:

to find the permiter of a rectangle you add the lengths of the rectangles four sides .

4 0
3 years ago
For a treasure hunt game, 300 balls are hidden. Of the balls that ate hidden, 40% of them are yellow and the rest are white. Sal
Mamont248 [21]
300*.4=120
300-120=180

there are 120 yellow balls and 180 white balls.

120*.2=24
180*.8=144

sallys team found 168 balls

4 0
3 years ago
Read 2 more answers
If a = pi +3j - 7k, b = pi - pj +4k and the angle between a and is acute then the possible values for p are given by​
PIT_PIT [208]

Answer:

The family of possible values for p are:

(-\infty, -4) \,\cup \,(7, +\infty)

Step-by-step explanation:

By Linear Algebra, we can calculate the angle by definition of dot product:

\cos \theta = \frac{\vec a\,\bullet\,\vec b}{\|\vec a\|\cdot \|\vec b\|} (1)

Where:

\theta - Angle between vectors, in sexagesimal degrees.

\|\vec a\|, \|\vec b \| - Norms of vectors \vec {a} and \vec{b}

If \theta is acute, then the cosine function is bounded between 0 a 1 and if we know that \vec {a} = (p, 3, -7) and \vec {b} = (p, -p, 4), then the possible values for p are:

Minimum (\cos \theta = 0)

\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} > 0

Maximum (\cos \theta = 1)

\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} < 1

With the help of a graphing tool we get the family of possible values for p are:

(-\infty, -4) \,\cup \,(7, +\infty)

7 0
3 years ago
How do I simplify 6y-y
aniked [119]
Think of 6y as

y + y + y + y + y + y

Now subtract a y from that.

y + y + y + y + y + y - y = y + y + y + y + y = 5y
8 0
4 years ago
Read 2 more answers
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