1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Varvara68 [4.7K]
3 years ago
5

HELP ME PLS OMG -LS PLS PLS PLS ASAP ASAP PLS pls ASAP

Mathematics
2 answers:
Vlada [557]3 years ago
7 0

Answer:

aab ggg7ih8h7g6d gdcc

Sedaia [141]3 years ago
5 0
I believe that the answer is false, true, true. Because you can’t solve this equation with the Pythagorean theorem, the solution s to the equation are x=4 and x=0, and finally if you wanted to you could subtract 6 from both sides first.
You might be interested in
I need help asap !!!!!!
Fittoniya [83]

Answer:(6, -4)

Step-by-step explanation: That’s where they meet at point B

4 0
2 years ago
Read 2 more answers
What are the common factor of the numbers; 15,45,90,135
Citrus2011 [14]
The common factor of the numbers is 15
3 0
3 years ago
Kira drives a truck for a soft drink company. Her truck is filled with 15 -ounce cans and 70 -ounce bottles. Let c be the number
svet-max [94.6K]
15c + 70b < 4000 lbs
THE SIGN SHOULD HAVE A LINE UNDER IT FOR EQUAL TO! :)
hope this helps!
4 0
3 years ago
URGENT PLEASE HELP. IXL IS TOUGH
guajiro [1.7K]

Answer:

so first get your calc out and type in the formula once you do that but 16 times 7 and equal it than divide it and tell me what you get

Step-by-step explanation:

3 0
3 years ago
The doubling period of a bacterial population is 15 minutes. At time t= 80 minutes, the bacterial population was 90000​
Papessa [141]

Answer:

here i finished!

hope it helps yw!

Step-by-step explanation:

The doubling period of a bacterial population is 15 minutes.

At time t = 90 minutes, the bacterial population was 50000.

Round your answers to at least 1 decimal place.

:

We can use the formula:

A = Ao*2^(t/d); where:

A = amt after t time

Ao = initial amt (t=0)

t = time period in question

d = doubling time of substance

In our problem

d = 15 min

t = 90 min

A = 50000

What was the initial population at time t = 0

Ao * 2^(90/15) = 50000

Ao * 2^6 = 50000

We know 2^6 = 64

64(Ao) = 50000

Ao = 50000/64

Ao = 781.25 is the initial population

:

Find the size of the bacterial population after 4 hours

Change 4 hr to 240 min

A = 781.25 * 2^(240/15

A = 781.25 * 2^16

A= 781.25 * 65536

A = 51,199,218.75 after 4 hrs

6 0
3 years ago
Other questions:
  • One year Hank had the lowest ERA (earned-run average, mean number of runs yielded per nine innings pitched) of any male pitcher
    9·1 answer
  • Write an expression for "10 multiplied by u
    9·2 answers
  • Anna has an online checking account at Garden city Bank. Her balance at the beginning of February was $5195.65. During the month
    11·1 answer
  • Can the fraction 12/27 be reduced
    11·2 answers
  • Which statement is true about the function f(x) minus the square root of x
    11·1 answer
  • I need help <br> 5times 10 +25-9+2times2
    5·2 answers
  • Michael bought 4 types of fruit to make a fruit salad. He paid $3.00 per pound of apples, $2.00 per pound for bananas, $2.50 per
    9·2 answers
  • Compute:<br><br> 11^2−(12−4)^2+3=
    8·2 answers
  • Simplify: 5(<br> 6-3) + 2
    14·1 answer
  • Convert 36°F to degrees Celsius.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!