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3 years ago

HELP ME PLS OMG -LS PLS PLS PLS ASAP ASAP PLS pls ASAP

Mathematics

2 answers:

Vlada [557]3 years ago

7 0

Answer:

aab ggg7ih8h7g6d gdcc

Sedaia [141]3 years ago

5 0

I believe that the answer is false, true, true. Because you can’t solve this equation with the Pythagorean theorem, the solution s to the equation are x=4 and x=0, and finally if you wanted to you could subtract 6 from both sides first.

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Find the value of x (approximately),

tresset_1 [31]

Answer:. If the Area is 177, it should have been given in square centimeters.

If one side is 13 cm, the other side is about 13.6cm.

If one side is 11 cm, the other side should be about 16.1 cm. Even the choice is incorrect!

A/x = w

Step-by-step explanation: to find a side when the Area is given, divide the Area by the length or width given.

5 0

3 years ago

HELP MARKING BRAINLIEST EXTRA POINTS !!

Scrat [10]

Answer:

The quadrilateral is a rectangle
$Perimeter=8\sqrt{2} \,\,Unit$
$Area=6\,\,sq.unit$

Step-by-step explanation:

Given,

$A=(0,0)\\B=(1,1)\\C=(4,-2)\\D=(3,-3)$

Now,

$Slope\,\,for\,\,AB=\frac{1-0}{1-0} =1\\\\Slope\,\,for\,\,CD=\frac{-3+2}{3-4} =1\\\\Slope\,\,for\,\,AD=\frac{-3-0}{3-0} =-1\\\\Slope\,\,for\,\,BC=\frac{-2-1}{4-1} =-1\\\\So,AB||CD\,\,and\,\,AD||BC$

$AB=\sqrt{(1-0)^2+(1-0)^2}=\sqrt{2}\\BC=\sqrt{(4-1)^2+(-2-1)^2}=3\sqrt{2}\\CD=\sqrt{(3-4)^2+(-3+2)^2}=\sqrt{2}\\AD=\sqrt{(3-0)^2+(-3-0)^2}=3\sqrt{2}\\\\So,\,\,AB=CD,AD=BC\\The\,\,quadrilateral\,\,is\,\,a\,\,rectangle$

$Perimeter=2*(AB+AD)=2*(BC+CD)\\=2*(\sqrt{2}+3\sqrt{2})=8\sqrt{2} \,\,Unit$

$Area=AB*AD=BC*CD=\sqrt{2} *3\sqrt{2}=6\,\,sq.unit$

Hope you have understood this.....

ask me if you have any confusion.....

if you liked it pls mark it as the brainliest

5 0

3 years ago

Loan a banko Q Mr shatish took of $ 12000 from The interest of for annum gives 5% per 3 years 3

lapo4ka [179]

Answer:

interest: 1,800

total: 13,800

Step-by-step explanation:

7 0

2 years ago

A) Work out the value of 5^2 – 1^5× 2^4<br>b) Work out the value of 7^2 + 4^3 ÷ 2^5

NemiM [27]

First you have to know BODMAS/BIDMAS (idk if all schools teach it like this) but this is the order in which you complete questions so it’s Brackets, Indices, Division/Multiplication, Addition/Subtraction
a) 5^2 is 5x5 which equals 25 1 to the power of anything is always 1 and 2^4 is 2x2x2x2 which is 16
So 5^2-1^5x2^4 = 25-1x16 which is then 25-16 = 9
b) 7^2+4^3 divided by 2^5 so 7^2 is 7x7 which = 49 then 4^3 means 4x4x4 = 64 and 2^5 is 2x2x2x2x2 which equals 32 so
7^2+4^3 divides by 2^5 is 49+64/32 = 49+2 which is 51

8 0

3 years ago

Find the standard form of the equation of the parabola with a focus at (0, 8) and a directrix at y = -8.

Gala2k [10]

Vertex is directly in middle of directix and focus

distance from 8 to -8 is 16
16/2=8
so 8 below focus (since 8>-8) is the point (0,0
vertex is (0,0)
nice

it opens up because focus is above directix
also it goes up down so
4p(y-k)=(x-h)^2
(h,k) is veretx
we got that (h,k) is (0,0)
and p is distance from vertex to focus which is 8
so
4(8)(y-0)=(x-0)^2
32y=x^2
y=(1/32)x^2

5 0

3 years ago