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2 years ago

Convert 36°F to degrees Celsius.

Mathematics

1 answer:

daser333 [38]2 years ago

5 0

Step-by-step explanation:

2.2

it is the answer

I hope it helps

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Given the equation...

Semenov [28]

Should be all real numbers

8 0

2 years ago

188 to 42 what is the percent change

Mekhanik [1.2K]

Answer:

Step-by-step explanation:

so we are gonna have a percent decrease because it went from 188 to 42

decrease = (original number - new number) / (original number ) * 100

= (188 - 42) / (188) * 100

= (146 / 188) * 100

= 0.7766 * 100

= 77.66% decrease....not sure if u need ur answer rounded to the nearest percent or not....if so, its a 78% decrease

6 0

3 years ago

Which fraction is equivalent to 6/-8? Please help! It will be appreciated

Bas_tet [7]

Answer:

it would be the last one

Step-by-step explanation:

hope it helps

7 0

2 years ago

Read 2 more answers

write an equation for an ellipse centered at the origin, which has foci at (+-3,0) and co vertices at (0+-4)

natali 33 [55]

Answer:

The equation for an ellipse centered at the origin with foci at (-3, 0) and (+3, 0) and co-vertices at (0, -4) and (0, +4) is:

$\frac{x^{2}}{7} + \frac{y_{2}}{16} = 1$

Step-by-step explanation:

An ellipse center at origin is modelled after the following expression:

$\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1$

Where:

$a$ , $b$ - Major and minor semi-axes, dimensionless.

The location of the two co-vertices are (0, - 4) and (0, + 4). The distance of the major semi-axis is found by means of the Pythagorean Theorem:

$2\cdot b = \sqrt{(0-0)^{2}+ [4 - (-4)]^{2}}$

$2\cdot b = \pm 8$

$b = \pm 4$

The length of the major semi-axes can be calculated by knowing the distance between center and any focus (c) and the major semi-axis. First, the distance between center and any focus is determined by means of the Pythagorean Theorem:

$2\cdot c = \sqrt{[3 - (-3)]^{2}+ (0-0)^{2}}$

$2\cdot c = \pm 6$

$c = \pm 3$

Now, the length of the minor semi-axis is given by the following Pythagorean identity:

$a = \sqrt{b^{2}-c^{2}}$

$a = \sqrt{4^{2}-3^{2}}$

$a = \pm \sqrt{7}$

The equation for an ellipse centered at the origin with foci at (-3, 0) and (+3, 0) and co-vertices at (0, -4) and (0, +4) is:

$\frac{x^{2}}{7} + \frac{y_{2}}{16} = 1$

4 0

3 years ago

For what values of x is the quantity x + 5 negative? Enter your answer as an inequality.

tangare [24]

Answer:

x < -6

Step-by-step explanation:

Whenever the value of x will be less than -6 the answer is going to be negative.

i hope it will help you!

5 0

3 years ago