Question

A three inch diameter pulley on an electric motor that runs at 1800

Answer 1

Answer:

a) 3 inch pulley: 11,309.7 radians/min

6) 6 inch pulley: 5654.7 radians/min

b) 900 RPM (revolutions per minute)

Step-by-step explanation:

Hi!

When a pulley wirh radius R rotantes an angle θ, the arc length travelled by a point on its rim is Rθ.  Then the tangential speed V is related to angular speed  ω as:

$V=R\omega$

When you connect two pulleys with a belt, if the belt doesn't slip, each point of the belt has the same speed as each point in the rim of both pulleys: Then, both pulleys have the same tangential speed:

$\omega_1 R_1 = \omega_2 R_2$

$\omega_2 = \omega_1 \frac{R_1}{R_2} =1800RPM* \frac{3}{6}= 900RPM$

We need to convert RPM to radias per minute. One revolution is 2π radians, then:

$\omega_1 = 1800*2\pi \frac{radians}{min} = 11,309.7\frac{radians}{min}$

$\omega_2 = 5654.7 \frac{radians}{min}$

The saw rotates with the same angular speed as the 6 inch pulley: 900RPM