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3 years ago

Will give correct answer brainliest

Mathematics

1 answer:

evablogger [386]3 years ago

3 0

ST ~ FM

T ~ M

JS ~ BF

S ~ F

hope this hellpss

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Find Each Sum. (–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd) =

tia_tia [17]

To add monomials, you have to look at the variables that are accompanied by their coefficients. In the given problem, (–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd), you can combine both cd ut nt cd and c² and cd and d and d and c² because they have different variables.

(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd)
(-4c² + 8c²) + (7cd + 4cd) + (8d - 3d)
4c² + 11cd + 5d

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3 years ago

Claire paid $5.75 for a movie ticket. She wants to buy popcorn for $4.95 and a drink for $3.98. Claire brought $15 to the theate

Evgesh-ka [11]

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4 0

3 years ago

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Write each expression as a single power of 10

swat32

Answer:

It is

${10}^{5}$

Step-by-step explanation:

$\frac{ {10}^{4}. {10}^{5} . {10}^{6} }{ {10}^{3} . {10}^{7} } = \frac{ {10}^{(4 + 5 + 6)} }{ {10}^{(3 + 7)} } \\ \\ = \frac{ {10}^{15} }{ {10}^{10} } \\ \\ = {10}^{(15 - 10)} \\ = {10}^{5}$

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3 years ago

The volume of a cone is 16 pi cubic inches. Its height is 12 inches. What is the radius of the cone? 2 in. 4 in. 12 in. 16 in.

mart [117]

The radius of cone is 2 inches

Solution:

The volume of cone is given by formula:

$V = \frac{\pi r^2h}{3}$

Where,

"V" is the volume of cone

"r" and "h" are the radius and height of cone respectively

Given that, volume of a cone is 16 pi cubic inches

Its height is 12 inches

Therefore, we get,

V = $16 \pi$ cubic inches

h = 12 inches

r = ?

Substituting the values in formula, we get

$16 \pi = \frac{ \pi \times r^2 \times 12}{3}\\\\16 = 4r^2\\\\r^2 = 4\\\\r = \pm 2$

Since, radius cannot be negative, ignore r = -2

Thus radius of cone is 2 inches

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3 years ago

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In what quadrant will θ terminate, if sin θ is positive and sec θ is negative?

kow [346]

Sin x is possitive in two quadrants :

quadrant I and quadrant II

in quadrant I, cos x is positive

in quadrant II , cos x is negative

so i think the answer is : quadrant II

hope this helps

5 0

3 years ago