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rjkz [21]
4 years ago
10

Can you simplify 5ths

Mathematics
2 answers:
Anastaziya [24]4 years ago
8 0
You can't simplify 5ths because you only divide by one
aev [14]4 years ago
6 0
You cannot simplify fifths because it is a prime number. Prime numbers are only divisible by 1 and itself.
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After doing some work in the house, Bob and Carol want to put a concrete patio on the side of the house to keep people from trac
12345 [234]

Answer:

V=3.098 yd³

Step-by-step explanation:

To answer this question we need to work with formula of the Volume of rectangular prism, the patio. Once it is required 1 inch deep. Some relations will be useful.

As 1 yard = 1 feet/3

1 yard = 1 inch/36

1 feet=12 inches

a) 23 feet 9 inches

23 ft 9''=23 +9/12=23.75 ft

b)10 feet  1 inch

10 feet  1" = 10ft + 1/12=10.083 ft

c)4 inches: 4/12 =0.33

V= w.l.h

V=23.75*10.083*0.33=79.025 ft³

Converting from cubic yard to cubic feet:

V≈79.025 : 27 yd³=2.926 yd³

Considering the possible spillage due to uneven base. ( adding 5%of V)

V≈ 2.92+0.05*(2.92)=3.098 yd³

4 0
3 years ago
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Mary had five and one half dollars she spent two and one fourth dollars on a snack how much money does Mary have left
Daniel [21]

Answer:

3 and 1/4

Step-by-step explanation:


3 0
3 years ago
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Pls help I am stuck on this question
Elanso [62]

Answer:

153.94 cm

Step-by-step explanation:

a = r^pi squared

r = d/2

7^pi = 21.98

21.98 squared = 153.94 cm

5 0
3 years ago
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SOMEONE PLEASE HELP ME WITH THIS QUESTION !!!
tatuchka [14]

Answer:

$700

Step-by-step explanation:

Given that:

Cost of desktop PC 10 years ago = $6000

Cost of desktop PC 2 years ago = $300

Linear model applies.

To find the rate of decrease per year, we need to find the slope.

One quantity is cost of PC here and second quantity here is number of years.

\text{Rate of decrease per year = }\dfrac{\text{Change in Price}}{\text{Change in Number of years}}

\Rightarrow \dfrac{6000-300}{10-2}\\\Rightarrow \dfrac{5700}{8}\approx \bold{\$700}

So, the answer is:

There is a decrease of <em>$700 </em>per year.

OR

Rate of decrease per year is <em>$700</em>.

7 0
3 years ago
please solve it please solve it please solve it please solve it please solve it please solve it please solve it please solve it
katovenus [111]

Since \alpha and \beta are roots of ax^2+bx+c, we can factorize the quadratic in terms of the roots as

ax^2+bx+c = a(x-\alpha)(x-\beta)

Expanding the right side gives

ax^2+bx+c = ax^2-a(\alpha+\beta)x+a\alpha\beta

so that

\alpha + \beta = -\dfrac ba \\\\ \alpha\beta = \dfrac ca

A polynomial with roots \alpha^2 and \beta^2 would be

(x-\alpha^2)(x-\beta^2)

and expanding this gives

x^2 - (\alpha^2+\beta^2)x+\alpha^2\beta^2

Now,

\alpha\beta = \dfrac ca \implies \alpha^2\beta^2 = (\alpha\beta)^2 = \dfrac{c^2}{a^2}

and

(\alpha+\beta)^2 = \alpha^2 + 2\alpha\beta + \beta^2 \\\\ \implies \alpha^2+\beta^2 = \left(-\dfrac ba\right)^2 -2\left(\dfrac ca\right) = \dfrac{b^2-2ac}{a^2}

So we can write the second quadratic in terms of a,b,c as

(x-\alpha^2)(x-\beta^2) = x^2 - \dfrac{b^2-2ac}{a^2}x + \dfrac{c^2}{a^2}

and to make things look cleaner, scale the whole expression by a^2 to get

\boxed{a^2x^2 + (2ac-b^2)x + c^2}

4 0
3 years ago
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