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3 years ago

Can you simplify 5ths

Mathematics

2 answers:

Anastaziya [24]3 years ago

8 0

You can't simplify 5ths because you only divide by one

aev [14]3 years ago

6 0

You cannot simplify fifths because it is a prime number. Prime numbers are only divisible by 1 and itself.

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Which translation maps the graph of the function f(x)=x2 onto the function g(x)= -8x+x2+7

marysya [2.9K]

Answer: Left 1 unit, up 5 units

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3 years ago

Find the image of A(-2,4) under a translation (x,y)->(x-2,y-3)

vichka [17]

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Point A would be at the coordinates, (-4, 1). Hope this helps!

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2 years ago

People attending a football game either supported the home team or the visiting team. If 1369 of the people attending supported

Anna [14]

Answer:

37%

Step-by-step explanation:

To find the percentage of people that supported the home team, we need to find the total number of people.

This is because the percentage of people supporting the home team will be given by:

Number of people supporting home team / total number of people

The total number of people is the people supporting the home team plus the people supporting the visiting team:

1369+2331=3700

Therefore, our percentage will be:

1369/3700

Plug this into our calculator and we get:

0.37

Convert that a percentage for a final answer of 37%

7 0

2 years ago

Read 2 more answers

IgorLugansk [536]

If you divide the numbers on the bigger triangle by 5 you get the numbers on the smaller one

7 0

3 years ago

Simplify : (√x + √y ) (√x − √y) (x + y)(x2 + y2)

Ivan

$Solution, \mathrm{Expand}\::\left(\sqrt{x}+\sqrt{y}\right)\left(\sqrt{x}-\sqrt{y}\right)\left(x+y\right)\left(x^2+y^2\right):\quad :x^4-:y^4$

$Steps:$

$\mathrm{Expand}\:\left(\sqrt{x}+\sqrt{y}\right)\left(\sqrt{x}-\sqrt{y}\right):\quad x-y, =\left(x-y\right)\left(x+y\right)\left(x^2+y^2\right)$

$\mathrm{Expand}\:\left(x-y\right)\left(x+y\right):\quad x^2-y^2, =:\left(x^2-y^2\right)\left(x^2+y^2\right)$

$\mathrm{Expand}\:\left(x^2-y^2\right)\left(x^2+y^2\right):\quad x^4-y^4, =:\left(x^4-y^4\right)$

$\mathrm{Expand}\::\left(x^4-y^4\right):\quad :x^4-:y^4, =:x^4-:y^4$

The correct answer is $x^4-y^4$

Hope this helps!!!

4 0

3 years ago