Answer:
I got that AE^2 = 8EC^2
Step-by-step explanation:
Here's what I did. I probably did this wrong, but this might give you an idea on how to solve it.
First, create equations:
AB = BC = AC = DE = 2EC
BD= BC = EC
Then, I used pythagorean theorem (since AD is perpendicular to BC): AD^2 + DE^2 = AE^2
Substitute: (2EC)^2 + (2EC)^2 = AE^2
Simplify: 4EC^2 + 4EC^2 = AE^2
AE^2 = 8CE^2
Answer:
2.79 * 10^4
Step-by-step explanation:
6.4 x 10^3+ 1.4 x 10^4+ 7.5 x 10^3
The exponents need to be the same
6.4 x 10^3+ 14 x 10^3+ 7.5 x 10^3
Add the numbers
6.4 + 14+ 7.5 =27.9
Multiply by the exponent
27.9 * 10 ^3
But this is not in scientific notation
Move the decimal one place to the left and add one to the exponent
2.79 * 10^4
So, there are two equations.
5a + 3c = 30
a + c = 8, therefore, a = 8 - c
5a + 3c = 30
5(8 - c) + 3c = 30
40 - 5c + 3c = 30
-2c = -10
c = 5 , So a = 3