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Otrada [13]
3 years ago
10

Circle Y is shown. 2 chords intersect. Angle 1 intercepts an arc with measure 37 degrees. Angle 2 intercepts an arc with measure

25 degrees. In circle Y, what is m∠1? 6° 25° 31° 37°
Mathematics
2 answers:
Vladimir79 [104]3 years ago
8 0

Answer:

31

Step-by-step explanation:

just took the edg test

Natalija [7]3 years ago
4 0

Answer:

The question is incomplete. It can be found in search engines. However, kindly find the solution below:

Let us first define what an intersecting coed is:

The intersecting chords theorem says that if two chords intersect inside a circle, then the measure of the angle produced is one half the sum of the measure of the arcs intercepted by the angle and its vertical angle.

Therefore,

First of all we will add the 2 angles

37° + 25°= 62°

The answer for that would be 62.

Now referring back to the theorem of intersecting cords that if two chords intersect inside a circle, then the measure of the angle produced is one half the sum of the measure of the arcs intercepted by the angle and its vertical angle.

Then, moving forward,

we will take half of that which is 62/2

It would give us  31

So angle 1 would be equal to 31

Hence,

m<1 = 1/2 x (37+25)

m<1 = 31°

So the answer for this question is 31°

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Marianna [84]

Answer:

11.44% probability that exactly 12 members of the sample received a pneumococcal vaccination.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they received a pneumococcal vaccination, or they did not. The probability of an adult receiving a pneumococcal vaccination is independent of other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

70% of U.S. adults aged 65 and over have ever received a pneumococcal vaccination.

This means that p = 0.7

20 adults

This means that n = 20

Determine the probability that exactly 12 members of the sample received a pneumococcal vaccination.

This is P(X = 12).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 12) = C_{20,12}.(0.7)^{12}.(0.3)^{8} = 0.1144

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3 0
3 years ago
1
Tcecarenko [31]

Answer:

It is not possible for the student to receive an A grade in the class.

It is possible for the student to receive a B grade in the class.

Step-by-step explanation:

We are given that in the DBE 122 class, there are 350 possible points. These points come from 5 homework sets that are worth 10 points each and 3 exams that are worth 100 points each.

A student has received homework scores of 7, 8, 7, 5, and 8, and the first two exam scores are 81 and 80.

Firstly, we will calculate how many points have been scored by the student.

Number of possible points = 350

The points scored by the student in homework = 7 + 8 + 7 + 5 + 8 = 35 points.

The scores of the student on the two exams = 81 + 80 = 161 points

So, the total points scored by the students = 35 + 161 = 196 points.

As it is given in the question that if the grade percentage is 0.9 or higher then the student will get an A, i.e;

If the total possible points are 350 points; 90\% \text{ of } 350 = \frac{90}{100}\times 350 = 315 \text{ points}

This means that the student must have to score 315 points to get an A grade.

Till the second exam, the total points scored by the students are 196 points. If the student scored full 100 marks in the third exam, then the total points scored by the student will be = 196 + 100 = 296 points.

Since 296 < 315, this means that it is not possible for the student to receive an A in the class.

Also, it is given in the question that if the grade percentage is between 0.8 and 0.9 the student will get a B, i.e, the student must obtain a minimum of 80% to get B grade.

If the total possible points are 350 points; 80\% \text{ of } 350 = \frac{80}{100}\times 350 = 280 \text{ points}

This means that the student must have to score a minimum of 280 points to get a B grade.

Till the second exam, the total points scored by the students are 196 points. If the student scored full 100 marks in the third exam, then the total points scored by the student will be = 196 + 100 = 296 points.

Since 296 > 280, this means that it is possible for the student to receive a B grade in the class.

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