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Nezavi [6.7K]
3 years ago
12

X/7=3/2 solve equation, check solution​

Mathematics
1 answer:
nexus9112 [7]3 years ago
6 0

Answer:

Step-by-step explanation:

X/7=3/2  multiply by : 5

x = 21/2

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It cost you $12 to start up your
brilliants [131]

Step-by-step explanation:

let no. of hours be x.

45x - 12 ≥ 117

45x ≥ 129

x ≥ 2.8667 (5sf)

therefore, 3 hours (round up to next whole number).

Topic: inequalities

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6 0
2 years ago
A tree broke 6 feet from the bottom. If the top landed 12 feet from the base, how tall was the tree before it broke?
spayn [35]

Answer:

7.4 ft

Step-by-step explanation:

7 0
2 years ago
The mean amount purchased by a typical customer at Churchill's Grocery Store is $26.00 with a standard deviation of $6.00. Assum
Vadim26 [7]

Answer:

a) 0.0951

b) 0.8098

c) Between $24.75 and $27.25.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 26, \sigma = 6, n = 62, s = \frac{6}{\sqrt{62}} = 0.762

(a)

What is the likelihood the sample mean is at least $27.00?

This is 1 subtracted by the pvalue of Z when X = 27. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{27 - 26}{0.762}

Z = 1.31

Z = 1.31 has a pvalue of 0.9049

1 - 0.9049 = 0.0951

(b)

What is the likelihood the sample mean is greater than $25.00 but less than $27.00?

This is the pvalue of Z when X = 27 subtracted by the pvalue of Z when X = 25. So

X = 27

Z = \frac{X - \mu}{s}

Z = \frac{27 - 26}{0.762}

Z = 1.31

Z = 1.31 has a pvalue of 0.9049

X = 25

Z = \frac{X - \mu}{s}

Z = \frac{25 - 26}{0.762}

Z = -1.31

Z = -1.31 has a pvalue of 0.0951

0.9049 - 0.0951 = 0.8098

c)Within what limits will 90 percent of the sample means occur?

50 - 90/2 = 5

50 + 90/2 = 95

Between the 5th and the 95th percentile.

5th percentile

X when Z has a pvalue of 0.05. So X when Z = -1.645

Z = \frac{X - \mu}{s}

-1.645 = \frac{X - 26}{0.762}

X - 26 = -1.645*0.762

X = 24.75

95th percentile

X when Z has a pvalue of 0.95. So X when Z = 1.645

Z = \frac{X - \mu}{s}

1.645 = \frac{X - 26}{0.762}

X - 26 = 1.645*0.762

X = 27.25

Between $24.75 and $27.25.

3 0
3 years ago
bill is on the school archery team. the target has a center bull's-eye and two rings around the bull's-eye. the table gives the
solong [7]

add the 2 probabilities together:

0.297 + 0.423 = 0.72

 Answer is C


3 0
3 years ago
Can someone help me with this question "Given the triangle below, what is m (angle) < B, rounded to the nearest tenth?
JulsSmile [24]
The answer
the sum of the angles in a triangle is always 180°
m < B + m < A + m < C = 180°,  
let's find m < B, 
by applying sinus rule 
 14/sinB=10/sinC, so sinB= 10xsinB = 14 x sinC and therefore, 
sinB=( 14/10 )sinC =7/2 sin 36° =0.82, so arcsinB=55.08°
the answer is C 55.4°



8 0
3 years ago
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