x^4 - 1
-------------
x^2 + 1
(x^2 +1) (x^2 - 1)
= ------------------------
x^2 + 1
= x^2 - 1 ..................this is your answer
Answer:
Step-by-step explanation:
n, n+2, n+4
2(n+2)-n=11
2n+4-n=11
n+4=11
n=7
So the three consecutive odd terms are 7, 9, 11.
If two dices are rolled once, you would have a total number of 6*6=36 possibilities.
To get a sum greater than 10:
A) one of your dices could be showing a 5, the other a 6. That’s two possibilities. Dice A being the 5 or dice B being the 5.
B) both of your dices could be showing 6s.
That’s one possibility.
So your overall possibility to get a sum greater than 10 is (1+2)/36 3/36=1/12
One twelfth.
If he goes to bed at 9:00 pm, and wakes up at 10:00 am he will have slept 13 hours.
